Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:

(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:

Compute the probability of a person having a heart attack given that he or she has the disease:

The probability of a person having a heart attack given that he or she has the disease is 0.595.
Answer:
x=0
Step-by-step explanation:
Anything divided by 0 is undefined so in this case 1/0 would be undefined.
Answer:
C
Step-by-step explanation:
y = mx + c
m = (y2 - y1 )/ (x2 - x1)
using (1 , 7) & (2,5)
y2 = 5 y1 = 7 so y2 -y1 = -2
x2 = 2 x1 = 1 so x2 - x1 = 1
m - -2/1 = -2
y = -2x + c
when x =1 y = 7
so 7 = -2 + c
=> c =9
y = -2x + 9
if ordered pairs (2, 5) and (4, 1) used
m = (1-5)/(4-2)
=> m = -4/2
=> m = -2
y = -2x + c
for x =2 y =5
5 = -2*2 + c
=> c = 9
y = -2x + 9
she would have got same equation
It is basically the halfway through the circle