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Stolb23 [73]
3 years ago
15

lign="absmiddle" class="latex-formula">
Mathematics
1 answer:
sashaice [31]3 years ago
3 0
Don’t now the answer sorry
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Step-by-step explanation:

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How do you write 5h+3k in a word form
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A ball is thrown straight up into the air from the top of a building standing at 50 feet with an initial velocity of 65 feet per
Lorico [155]

Answer:

0.5 seconds (at 100 feet in the air).

Step-by-step explanation:

So, the height of the ball can be modeled by the function:

h(t)=-16t^2+16t+96

Where h(t) represents the height in feet after t seconds.

And we want to find its maximum height.

Notice that our function is a quadratic.

Therefore, the maximum height will occur at the vertex of our function.

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In our function, a=-16; b=16; and c=96.

Find the x-coordinate of the vertex:

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So, the ball reaches its maximum height after 0.5 seconds of its projection.

Notes:

To find it’s maximum height, we can substitute 1/2 for our function and evaluate. So:

h(1/2)=-16(1/2)^2+16(1/2)+96

Evaluate:

h(1/2)=-4+8+96=100

So, the ball reaches its maximum height of 100 feet 0.5 seconds after its projection.

8 0
3 years ago
Redo bc the last one was blurry
andrezito [222]
4. * 10^-9
4. * 10^10
6. * 10^7
4. * 10^-8
All rounded to the nearest whole number. Take the number given and move the decimal point to make the number less that 10 but greater than 1. The, count how many spaces you moved the decimal point, this will be the power of 10. If you moved the decimal point to the left, the power of 10 will be positive. If you moved it to the right, the power of 10 will be negative. Hope this helped!
7 0
3 years ago
If a truck has a mass 10 times greater than a car, how fast will the car have to move to have the same momentum as the truck whe
zavuch27 [327]

i.e truch weighs 500 lbs so the car weighs 50lbs. lets say thw truck goes 2 mph so thatll be 1000 for the car to reach 1000 you have to divide and youll get 20. so the car has to be ten times as fast as the truck
7 0
3 years ago
Read 2 more answers
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