Express the polynomial 6e^2+3e^3+1 in standard form and then classify it.
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a. The unit rate is 9 d per t
b. Find the graph in the attachment
To graph the line, we need to find its gradient or unit rate
<h3>a. How to calculate the unit rate of change of d with respect to t?</h3>Since t has an increase of 0.20 units in t corresponds to an increase of 1.8 units in d.
The gradient or unit rate of change is m = change in d/change in t
= Δd/Δt
Since
- Δd = +1.8 units and
- Δt = +0.2 units
So, substituting the values of the variables into the equation, we have
m = Δd/Δt
= + 1.8 units/+ 0.2 units
= 9 d per t
So, the unit rate is 9 d per t
<h3>b. The graph of the line</h3>
To graph the function, we need to know the equation of the graph.
So, the equation of a graph in gradient form is
m = (y - y')/(x - x') where (x', y') = (0, 0) since the graphs both start at the origin
Since m = 9, we have
m = (y - y')/(x - x')
9 = (y - 0)/(x - 0)
9 = y/x
y = 9x
So, the equation of the line is y = 9x
Find the graph in the attachment.
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