Answer:
the midpoint is (9,5). hope this helps
Answer: The mid-point of AC easy to calculate.
It is at ((5+3)/2,(5−1)/2)=(4,2) .
What you really asked was the coordinates of the point 3/4 of the way from A to C, and the calculation is very similar. I think of it as giving a “weighting” to the nearest point. So in this case we give a weighting of 3 to point C and 1 to point A.
Then =((5+3∗3)/4,(5−1∗3)/4)
So =(3½,½) .
CHECK:
Distance
2=(5−3½)2+(5−½)2
=(3/2)2+(9/2)2=9/4+81/4
=90/4
So the distance =310‾‾‾√/2
And the distance
2=(3½−3)2+(½+1)2
=1/4+9/4=10/4
And so the distance BC is 10‾‾‾√/2 which is indeed one third of the distance AB.
Step-by-step explanation:
Answer:
X=1
Step-by-step explanation: