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stira [4]
3 years ago
7

Can you help me solve for x?

Mathematics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

x = 12

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

10x-10 = 60 +4x+2

Combine like terms

10x-10 = 62+4x

Subtract 4x from each side

10x-4x -10 = 62 +4x-4x

6x -10 = 62

Add 10 to each side

6x-10+10 = 62+10

6x= 72

Divide by 6

6x/6 = 72/6

x = 12

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Multiply: ( sqrt 2x^3 + sqrt12x) (2*sqrt 10x^5 + sqrt 6x^2)
solmaris [256]

Answer:

c is the answer

Step-by-step explanation:

i just did it

5 0
3 years ago
What is the equation, in slope-intercept form, of the line that is perpendicular to the line
wolverine [178]

Answer:

y=3/2x+1

Step-by-step explanation:

y-4= -⅔(x-6)

y-4=-⅔x+4

y=-⅔x+4+4

(equation of line 1) y= -⅔x+8 gradient= -⅔

(line 2)gradient=3/2

note* the gradients of perpendicular lines multiplied result to -1

gradient=<u>y²-y²</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹

<u>3</u><u> </u>=<u>y</u><u>+</u><u>2</u>

<u> </u><u> </u>2. x+2

multiply both sides by 2(x+2)to remove the denominators

3(x+2)=2(y+2)

3x+6=2y+4

3x+6-4=2y

3x+2=2y

divide all sides by 2

3/2x+1=y

y=3/2x+1

8 0
3 years ago
Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui
Vesnalui [34]
<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

Also, Area of the box  = S x S x H  =  S²H

⇒ S²H = 2000

\implies H = \frac{2000}{S^2}

Substituting the value of H in (1), we get:

A = S^2 + 4 SH =  S^2 + 4 S(\frac{2000}{S^2}) =  S^2 + (\frac{8000}{S})\\\implies A  =  S^2 + (\frac{8000}{S})

Now, to minimize the area put :

(\frac{dA}{dS} ) = 0 \implies 2S  - \frac{8000}{S^2}  = 0\\\implies S^3 = 4000\\\implies S  = 15.874 \approx 16 cm

Putting the value of S  = 15.874 cm in the value of H , we get:

\implies H = \frac{2000}{S^2}  =  \frac{2000}{(15.874)^2} = 7.8937 cm

Hence, the dimensions of the given rectangular box are:

L  =   15.874 cm

B  = 15.874 cm

H = 7.8937 cm

3 0
4 years ago
2
Svetlanka [38]

Answer:

area of rectangle=l×b=2.4×5.8=13.92cm²

6 0
3 years ago
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Find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using it. lim x→0+ arcta
Thepotemich [5.8K]
The answer for your problem is shown on the picture.

8 0
3 years ago
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