Write anumerical expression below : a. add14 and x b. the product of 6 and y

The coordinates of the vertices for rectangle ABCD are A (2,4), B (6,10), C (9,8) and D (5,2). What

sweet [91]

Answer:

D. $\sqrt{65}$

Step-by-step explanation:

The computation of the length of a diagonal (AC or BD) of the rectangle is shown below:

As we know that

The Diagonal length of AC is

$= (x_2 - x_1)^2 + (y_2 - y_1)^2\\\\= (9 -2)^2 + (8 - 4)^2\\\\= (7)^2 + (4)^2$

$= \sqrt{49 + 16}\\\\= \sqrt{65}$

Therefore correct option is D.

3 0

2 years ago

Debbie wants to decorate 3 lampshade. The diameter of the top of each lampshade is 8 inches and the diameter of the bottom is 12

user100 [1]

156 pi or about 490.08845396 inches

8 0

3 years ago

Kanye and jay wanted to see who could run faster in a minute.They both started in the same spot and ran in different directions.

Lena [83]

Answer:

Kanye run faster.

Step-by-step explanation:

Given that,

Time = 1 min = 60 sec

Suppose, we find the speed of kanye and Jay.

According to number line,

Kanye covers the -160m distance and Jay covers the 140 m distance.

Negative sign shows the opposite direction.

We need to calculate the speed of Kanye

Using formula of speed

$v=\dfrac{d}{t}$

Where, v = speed

d = distance

t = time

Put the value into the formula

$v=\dfrac{160}{60}$

$v=2.66\ m/s$

We need to calculate the speed of Kanye

Using formula of speed

$v=\dfrac{d}{t}$

Put the value into the formula

$v=\dfrac{140}{60}$

$v=2.33\ m/s$

The speed of kanye is more than jay.

Hence, Kanye run faster.

6 0

3 years ago

4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B

AleksAgata [21]

Answer:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

$\hat p=\frac{63}{200}=0.315$ estimated proportion of lawyers had used some form of advertising for their business

$p_o=0.25$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

8 0

3 years ago

12x - 3x + 11 3 4x - (17 - 9x)

KengaRu [80]

sorry it won't let me show step by step but your answer is 150x-17

8 0

3 years ago

Read 2 more answers