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The answer is: <u>2(k2−4k)(2c+5)</u>
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Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
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Answer: The factorization of 
The factors of are 28 and 1+2t+w.
Step-by-step explanation:
The given expression :
To factorize it, we need to find the common factor.
As 56 can be written as 2 x 28.
So, the above expression would become
Now, taking 28 as common from all the terms, we will get
Thus, the factorization of
And the factors of are 28 and 1+2t+w.
Total tax paid = 1440
Tax rate = Rs 2 per Rs 100
ATQ
1440 ÷ 2
= 720
720 × 100
Rs 72,000
His income is Rs 72,000
Answered by Gauthmath must click thanks and mark brainliest
Simplify whatever is in the parenthesis:
(5×^2-4x-1) and <span>(4x^2-4)
after that subtract the numbers you got from both </span>parenthesis after simplifying
