3 years ago

This might be really easy, but what is the difference between a factor and a multiple between numbers?

Mathematics

1 answer:

kodGreya [7K]3 years ago

5 0

The possible multiples of any number are unlimited.
 While factors must be integers

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Divide the number 20 into two parts (not necessarily integers) in a way that makes the product of one part with the square of th

Ilya [14]

Answer:

13 1/3 and 6 2/3.

Step-by-step explanation:

Let the 2 parts be x and (20 - x).

So x^2(20 - x) must be a maximum.

y = x^2(20 - x)

y = 20x^2 - x^3

Finding the derivative):

y' = 40x - 3x^2 = 0 for maxm/minm value.

x( 40 - 3x) = 0

40 - 3x = 0

3x = 40

x = 40/3.

This is a maximum because the second derivative y" = 40 - 6x = 40 - 6(40/3)) is negative.

So the 2 numbers are 13 1/3 and 6 2/3.

3 0

3 years ago

Ginny buys 7 magazines for 2.80 how much does 1 cost? How much does do 5 magazine cost?

saw5 [17]

Answer:

one costs 0.40 and 5 cost 2.00

Step-by-step explanation:

bc 2.80/7 = 0.40

0.40 times 5 = 2.00

3 0

3 years ago

All of the students in sixth grade either purchased their lunch or brought their lunch from home on Monday.

Nat2105 [25]

Answer:

250

Step-by-step explanation:

1. 190 students is the number that is 100-24 = 76% of the 6th grade population

0.76x = 190

x = (190/.76) = 250

4 0

3 years ago

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is <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3to%20%5C%3A%20the%20%5C%3A%20power%20%5C%3A%20of%20%5C%3A%20100%7D%7B3to%20%5

Norma-Jean [14]

Remember the laws of exponents:

$\frac{a^n}{a^m}=a^{n-m}$

Then:

$\begin{gathered} \frac{3^{100}}{3^{99}}=3^{100-99} \\ =3^1 \\ =3 \end{gathered}$

Therefore:

$\frac{3^{100}}{3^{99}}=3$

7 0

1 year ago

Estimate the product 879x8

AnnZ [28]

7032 is the answer I hope it helps you

7 0

3 years ago

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