Question

How do I solve for d in the following equation? c(ad)+x=bd+ad(yz)

Answer 1

Easy
remember associative property
a(bc)=(ab)c
so theerfor we can move dem around
also rembmer distributive property and how it can be expanded
ab+ac=a(b+c) therefor
ab+ac+ad=a(b+c+d)

(ca)d+x=bd+d(ayz)
minus (ca)d from both sides
x=db+d(ayz)-d(ca)
undistribute d
x=d(b+ayz-ca)
divide both sides by (b+ayz-ca)
$\frac{x}{b+ayz-ca}=d$
$d=\frac{x}{b+ayz-ca}$