Easy remember associative property a(bc)=(ab)c so theerfor we can move dem around also rembmer distributive property and how it can be expanded ab+ac=a(b+c) therefor ab+ac+ad=a(b+c+d)
(ca)d+x=bd+d(ayz) minus (ca)d from both sides x=db+d(ayz)-d(ca) undistribute d x=d(b+ayz-ca) divide both sides by (b+ayz-ca)