The largest integers of the numbers is 406.
<h3>How to find the five consecutive positive integers?</h3>
The sum of five consecutive positive integers is 2020.
Therefore,
let
the first positive integer = x
Hence,
x + x + 1 + x + 2 + x + 3 + x + 4 = 2020
5x + 10 = 2020
5x = 2020 - 10
5x = 2010
x = 2010 / 5
x = 402
largest integer = 402 + 4 = 406
Therefore, the largest integers of the numbers is 406.
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Answer:7 2/35
Step-by-step explanation:
This is because of pemdas parenthesis exponents multiplication division addition and subtraction
Answer:
24 frames per second
Step-by-step explanation:
Answer:
y = 1.00+0.10 x
Step-by-step explanation:
Given that a taxi has a minimum charge of 1 dollar upto 1/10 mile and adds 0.10 for every additional 1/10 mile.
If a person travels <=1/10 miles his charges are 1 dollar
If he travels >1/10 miles charges are 1 dollar +0.10(extra miles 1/10)
Let y be the charges and x be the no of 1/10 miles.
Then the equation for y in terms of x would be
y =1.00 +1/10(x)
y = 1.00+0.10 x
Special Case is No
Domain = (-∞, ∞)
