X² + 6x -12 = 0
x = <u>-(6) +/- √((6)² - 4(1)(-12))</u>
2(1)
x = <u>-6 +/- √(36 + 48)</u>
2
x = <u>-6 +/- √(84)
</u> 2<u>
</u>x = <u>-6 +/- 2√(21)
</u> 2<u>
</u>x = -3 <u>+</u> √(21)
x = -3 + √(21) x = -3 - √(21)
What's the mean, median, and mode of 3, 5, 1, 5, 1, 1, 2, 3, 15.
lara [203]
<h3><em>
Answer:</em></h3>
<em>mean = 4</em>
<em>Median = 3</em>
<em>Mode = 1</em>
Step-by-step explanation:
first let’s arrange the numbers from least to highest:
1 , 1 , 1 , 2 , 3 , 3 , 5 , 5 , 15
=====================
The median is the number that’s comes in the middle of the data set ⇒ median = 3 ( the fifth number in the data set)
1 , 1 , 1 , 2 , <u>3</u>, 3 , 5 , 5 , 15
________________________
The mode is the number that repeats the most ⇒ mode = 1 (repeated 3 times)
____________________________________
Answer:
No picture...
Step-by-step explanation:
The following system is INCONSISTENT
Answer:
<u>Temperature of the ice for ice-skating = -5 °C</u>
Step-by-step explanation:
1. Let's review the information given to us for solving the question:
Temperature of the ice for an ice hockey match = - 7 °C
Temperature for ice- skating is 2 degrees warmer.
2. What is the temperature of the ice for ice-skating?
For the correct calculation, we use this formula:
Temperature for ice-skating = Temperature of the ice for a hockey match + 2
Temperature for ice-skating = -7 + 2
<u>Temperature of the ice for ice-skating = -5 °C</u>
We add 2 to the temperature of the ice for a hockey match because the temperature for ice-skating is described as warmer. If it were described as colder, we should subtract.
