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3 years ago

Given an equation x3 - 8x2 - 9x + 72 = 0, find the zeros.

Mathematics

1 answer:

sveta [45]3 years ago

7 0

Answer:

= 28/3

Step-by-step explanation:

Let's solve your equation step-by-step.

x(3)−(8)(2)−9x+72=0

Step 1: Simplify both sides of the equation.

x(3)−(8)(2)−9x+72=0

3x+−16+−9x+72=0

(3x+−9x)+(−16+72)=0(Combine Like Terms)

−6x+56=0

Step 2: Subtract 56 from both sides.

−6x+56−56=0−56

−6x=−56

Step 3: Divide both sides by -6.

−6x

−6

−56

−6

Answer:

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2 years ago

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List all the factor pairs for 48. make a table to help and add the table.

Feliz [49]

Answer:

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Step-by-step explanation:

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3 years ago

1. Choose the graph that represents the equation y = -x] - 1.

AVprozaik [17]

Answer:

x=−y−1

Step-by-step explanation:

y=−x−1

Step 1: Flip the equation.

−x−1=y

Step 2: Add 1 to both sides.

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5 0

3 years ago

The net of a pyramid is shown below:

Shalnov [3]

Answer:

Step-by-step explanation:

height of pyramid = √(10²-(5/2)²) = √93.75

volume of pyramid = ⅓b²h = ⅓·5²√93.75 ≅ 80.69 in³

lateral area = 2×5×10 = 100 in²

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surface area = 100+25 = 125 in²

6 0

2 years ago

I GIVE BRAINLIEST PLS HELP

ioda

The answer is 8
Here's why:
${ ( \frac{( {6}^{7}) \times ( {3}^{3}) }{( {6}^{6}) \times ( {3}^{4} ) } )}^{3} = \\ ( \frac{6}{3} ) ^{3} = \\ \frac{216}{27} = 8$
The exponents are subtracted one from another when divided.
$\frac{ a ^{b} }{ {a}^{c} } = {a}^{b - c}$
We can look at the problem this way:
$( \frac{6^{7} }{6 ^{6} } \times \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6} \times {3}^{3 - 4} ) = \\ ({6}^{1} \times {3}^{ - 1} )$
Since we have the power of -1 on the 3, we apply this rule:
${a}^{ - b} = \frac{1}{ {a}^{b} }$
Also this rule because we have the power of 1 on the 6:
${a}^{1} = a$
Then we get this:
$(6 \times \frac{1}{3} )^{3} = ( \frac{6}{3} )^{3}$
We apply the rule:
$( \frac{a}{b}) ^{c} = \frac{ {a}^{c} }{ {b}^{c} }$
We get this:
$\frac{{6}^{3} }{ {3}^{3} } = \frac{216}{27} = 8$

4 0

3 years ago