Screenwriter! A screenwriter's role is to pen the script for a film.
Answer:
Storage Size
Explanation:
the answer to which is better 8 Mbps or 2 MBps? Is 2 MBps (which is 16 Mbps). Using a less common, but more clear notation: which is better 8 Mbit/s or 2 MBps? Answer: 2 MBps, since that is 16 Mbit/s. (Marketing people use this confusion to their advantage if you're not sure which is intended, ask.)
Source http://cs.sru.edu/~mullins/cpsc100book/module02_introduction/module02-05_introduction.html
(if you want to read the full artical.)
Answer:
Point type is a horizontal or vertical line of text that begins where you click and expands as you enter characters. Each line of text is independent—the line expands or shrinks as you edit it, but doesn’t wrap to the next line. Entering text this way is useful for adding a few words to your artwork.
Select the Type tool or the Vertical Type tool .
The pointer changes to an I-beam within a dotted box. The small horizontal line near the bottom of the I-beam marks the position of the baseline, on which the text rests.
(Optional) Set text-formatting options in the Control panel, Character panel, or Paragraph panel.
Click where you want the line of text to begin.
Explanation:
Answer:
See attachment fir procedures to get answers.
Explanation:
Given that;
In the Database sheet, enter conditions in the criteria range for unoccupied two- and three-bedroom apartments that need to be remodeled. Enter criteria as text only, without use of quotation marks. Be sure to enter the criteria separately in rows 3 and 4.
See attachment
Answer:
Explanation:
The following code is written in Java and is a function/method that takes in an int array as a parameter. The type of array can be changed. The function then creates a counter and loops through each element in the array comparing each one, whenever one element is found to be a duplicate it increases the counter by 1 and moves on to the next element in the array. Finally, it prints out the number of duplicates.
public static int countDuplicate (int[] arr) {
int count = 0;
for(int i = 0; i < arr.length; i++) {
for(int j = i + 1; j < arr.length; j++) {
if(arr[i] == arr[j])
count++;
}
}
return count;
}
