It is Nevaeh backwards hope that helps! :3 and feel free to pm me if you have anymore questions! :3
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
Answer:
Explanation:
The answer is false
Because the 4 elements are shapes texture colour and size
Answer:
Explanation:
The following procedure is written in Python. It takes the next argument, checks if it is an odd number and if so it adds it to oddsum. Then it asks the user for a new number from the keyboard and calls the accumulator procedure/function again using that number. If any even number is passed the function terminates and returns the value of oddsum.
def accumulator(next, oddsum = 0):
if (next % 2) != 0:
oddsum += next
newNext = int(input("Enter new number: "))
return accumulator(newNext, oddsum)
else:
return oddsum
