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mojhsa [17]
3 years ago
6

Case Study 2

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer:

good for them i think

Step-by-step explanation:

this doesnt make any sense

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How do new substances form?
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New substances form when bonds break and new bonds form. The chemical properties of the new substances are different from those of the original substances

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A 28 foot ladder is propped against a wall. The base of the ladder is 19 ft from the wall how far up the wall does the ladder go
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20.6

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8 0
3 years ago
Solve 6x^2 - 42 = 0 for the exact values of x
GREYUIT [131]

Answer:

The values of x are

x=-\sqrt{7} , x=\sqrt{7}

Step-by-step explanation:

we have

6x^{2}-42=0

Solve for x

Adds 42 both sides

6x^{2}-42+42=0+42

6x^{2}=42

Divide by 6 both sides

6x^{2}/6=42/6

simplify

x^2=7

square root both sides

x=\pm\sqrt{7}

therefore

The values of x are

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6 0
3 years ago
After a glide reflection, the point x is mapped to the point x' (3,-2). The translation part of the glide reflection is (x,y) -&
Umnica [9.8K]

The coordinates of the original point <em>x</em>, can be obtained by reversing the given transformations individually

The coordinates of the original point <em>x</em> is \underline{(0, \, 0)}

Reason:

The type of reflection = Glide reflection

Coordinates of the image of the point <em>x</em> = x'(3, -2)

The translation part of the glide reflection is (x, y) → (x + 3, y)

The line of reflection is y = -1

The coordinates of the original point = Required

Solution:

  • A glide reflection is also known as a transflection, that involves a symmetric composite transformation of a reflection followed by a translation along the line of reflection

Reflection part;

The distance of the image point from the reflecting line = The object's

point distance from the reflecting line

Therefore, given that the reflecting line is the line y = -1, and the image

point is x'(3, -2), we have;

Distance of image from reflecting line =-1 - (-2) = 1

∴ Distance of object point from reflecting line = 1

y-coordinate of object point = -1 + 1 = 0

Point of image of the object before reflection and after translation = (3, 0)

Translation part;

The translation of the glide reflection is (x, y) → (x + 3, y)

Therefore, the location of the object before translation is ((x + 3) - 3, y), which from the point (3, 0) gives, ;

((3) - 3, 0) → (0, 0)

The coordinates of the original point <em>x</em> is \underline{(0, \, 0)}

Learn more here:

brainly.com/question/12890981

8 0
2 years ago
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