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Lerok [7]
4 years ago
8

A car initially traveling at 60 km/h accelerates at a constant rate of 2.0 m/s2. how much time is required for the car to reach

a speed of 90 km/h?4
Physics
1 answer:
bogdanovich [222]4 years ago
3 0
<span>since the car starts at 60 km/hr, first subtract the 60 from 90 km/hr which is 30. that is the acceleration we need to solve. 2.0 m/s multiply by 60 seconds in a minute, and 60 minutes in an hour, which equals 7200 m/s in an hour or divide by 1000 (1000 meters in a km) and have 7.2m an hour. divide the 30 km/hr by 7.2 and you have 4.167 hours. You could also take the 30 km/hr needed to accelerate to match the 90 km/hr and find the number of meters needed to accelerate which is 30,000. divide by 2 meters per second equals 15,000. divide by 60 seconds in a minute, and divide by 60 minutes in an hour which still equals 4.167 hours.</span>
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What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 1.200 kg of the substance increases i
Anarel [89]

Answer:

0.035 J/g°C

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) = 1.2 Kg

Initial Temperature (T₁) = 10 °C

Final Temperature (T₂) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial Temperature (T₁) = 10 °C

Final Temperature (T₂) = 70 °C

Change in temperature (ΔT) =

ΔT = T₂ – T₁

ΔT = 70 – 10

ΔT = 60 °C

Thus, the change in the temperature of the substance is 60 °C

Next, we shall convert 1.2 Kg to grams (g). This can be obtained as follow:

1 Kg = 1000 g

Therefore,

1.2 Kg = 1.2 Kg × 1000 g / 1 Kg

1.2 Kg = 1200 g

Thus, 1.2 Kg is equivalent to 1200 g.

Finally, we shall determine the specific heat capacity of substance. This can be obtained as follow:

Heat (Q) absorbed = 2500 J

Mass (M) = 1200 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 1200 × C × 60

2500 = 72000 × C

Divide both side by 72000

C = 2500 / 72000

C = 0.035 J/g°C

Therefore, the specific heat capacity of the substance is 0.035 J/g°C

3 0
3 years ago
The filament of an electric bulb draws a current of 0.4 ampere. Calculate the amount of charge flowing through the filament if t
Marina86 [1]
Here I =0.4 amp and t=2hr or 2×60×60 sec
We known I=nQ/t where Q is charge and n is no of charge.
n=It/Q
0.4x(2x60x60)/1.6x10^-19
3 0
3 years ago
What are the different intensity of an earthquake
Masja [62]

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

hope it helps

Mark as brainliest

and follow me for a follow back

5 0
3 years ago
A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o
dimulka [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is  m_1 = 81.14 \ kg

Explanation:

From the question we are told that

   Mass of the first block is  m_1 = 100 \  kg

   The height is  s =  1.0 \  m

   The time it takes it is  t = 1.40 \  s

 Generally from kinematic equation

       s =  ut + \frac{1}{2} at^2

Here u  is the initial velocity which zero given that it was at rest initially

So

     s =  0 * t + \frac{1}{2} at^2

=>  s =   \frac{1}{2} at^2

=> 1 =   \frac{1}{2}*  a *  (1.40 )^2

=>  a = 1.0204 \  m/s^2

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is  mathematically represented as

      mg - T = ma

=>   T  =  m g - ma

=>   T  =  m(g - a)

=>   T  =  877.96 \  N

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is  mathematically represented as  

     T - m_1g  =  m_1 a

=>   877.96  =  m_1 (a + g)

=>   877.96  =  m_1 (1.0204  + 9.8 )

=>   m_1 = 81.14 \ kg

5 0
3 years ago
How many newtons of force are represented by the following amount: 3 kg·m/sec^2?
Jet001 [13]
1N=1kg•m/s^2 so the answer is 3N
8 0
4 years ago
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