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MakcuM [25]
3 years ago
5

Line segment Q R , Line segment R S and Line segment S Q are midsegments of Î"WXY. Triangle R Q S is inside triangle X Y W. Poin

t R is the midpoint of side X Y, point S is the midpoint of side Y W, and point Q is the midpoint of side X W. The length of Q R is 2. 93 centimeters, the length of R S is 2. 04 centimeters, and the length of Q S is 2. 28 centimeters. What is the perimeter of Î"WXY? 11. 57 cm 12. 22 cm 12. 46 cm 14. 50 cm.
Physics
1 answer:
Whitepunk [10]3 years ago
8 0

The perimeter of ΔWXY is : ( D ) 14.5 cm

<u>Calculating the </u><u>perimeter </u><u>of ΔWXY</u>

QR = WY / 2

RS = XW / 2

QS = XY / 2

Given that : QR = 2.93 cm ,  RS = 2.04 cm,  QS = 2.28 cm

Therefore

Perimeter of ΔWXY = ∑ WY + XW + XY  

                                 = 2SR + 2QS + 2QR

                                 = 2(2.04) + 2(2.28) + 2(2.93)

                                 = 14.5 cm

Hence we can conclude that the perimeter of ΔWXY = 14.5 cm

learn more about perimeter calculations : brainly.com/question/24744445

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8. An effort force of 15 Newtons is applied to an ideal pulley system to lift up a 16 Newton object. If the effort force is exer
Sonbull [250]

Answer:

the distance that the object is raised above its initial position is 5.625 m.​

Explanation:

Given;

applied effort, E = 15 N

load lifted by the ideal pulley system, L = 16 N

distance moved by the effort, d₁ = 6 m

let the distance moved by the object = d₂

For an ideal machine, the mechanical advantage is equal to the velocity ratio of the machine.

M.A = V.R

M.A = \frac{Load}{Effort} = \frac{L}{E} \\\\V.R = \frac{disatnce \ moved \  by \ the \ effort}{disatnce \ moved \  by \ the \ load} = \frac{d_1}{d_2} \\\\For \ ideal \ machine; \ M.A = V.R\\\\\frac{L}{E} = \frac{d_1}{d_2} \\\\d_2 = \frac{E \times d_1}{L} \\\\d_2 = \frac{15 \times 6}{16} \\\\d_2 = 5.625 \ m

Therefore, the distance that the object is raised above its initial position is 5.625 m.​

3 0
3 years ago
What is the connection between angle of incidence and angle of reflection
Radda [10]

Answer:

The normal line divides the angle between the incident ray and the reflected ray into two equal angles. The angle between the incident ray and the normal is known as the angle of incidence. The angle between the reflected ray and the normal is known as the angle of reflection.

8 0
3 years ago
A line from the Brackett series of hydrogen has a wavelength of 1945nm (or 1.0979x10^7m). From which state did the electron orig
Zarrin [17]
We use the Rydberg Equation for this which is expressed as:

<span>1/ lambda = R [ 1/(n2)^2 - 1/(n1)^2]
</span>
where lambda is the wavelength, where n represents the final and initial states. Brackett series means that the initial orbit that electron was there is 4 and R is equal to 1.0979x10^7m<span>. Thus,
</span>
1/ lambda = R [ 1/(n2)^2 - 1/(n1)^2]
1/1.0979x10^7m = 1.0979x10^7m [ 1/(n2)^2 - 1/(4)^2]

Solving for n2, we obtain n=1.
5 0
3 years ago
Sort the units based on the measurement system they're used in
timurjin [86]

Answer:

Kelvin

Explanation:

fact as per the guideline given

7 0
3 years ago
An RLC circuit is used in a radio to tune into the radio lagos fm Station broadcasting at 93.5Hz. The resistance is 15ohms and t
bazaltina [42]

The characteristics of the RLC circuit allow to find the result for the capacitance at a resonance of 93.5 Hz is:

  • Capacitance is C = 1.8 10⁻⁶ F

A series RLC circuit reaches the maximum signal for a specific frequency, called the resonance frequency, this value depends on the impedance of the circuit.

            Z^2 = R^2 + ( wL - \frac{1}{wC} )^2  

Where Z is the impedance of the circuit, R the resistance, L the inductance, C the capacitance and w the angular velocity. The negative sign is due to the fact that the current in the capacitor and the inductor are out of phase.

In the case of resonance, the impedance term completes the circuit as a resistive system.

           wL - \frac{1}{wC} = 0  \\w^2 = \frac{1}{LC}  

           

Indicate that the inductance L = 1.6 H and the frequency f = 93.5 Hz.

Angular velocity and frequency are related.

         

         w = 2π f

           

Let's  substitute.

          C = \frac{1}{L ( 2 \pi f)^2 }  

 

Let's calculate.

         C = \frac{1}{1.6 \ ( 2\pi \ 93.5)^2}  

         C = 1.8 10⁻⁶ F

In conclusion with the characteristics of the RLC circuits we can find the result for the capacitance at a 93.5 Hz resonance is:

  • Capacitance is C = 1.8 10⁻⁶ F

Learn more about serial RLC circuits here: brainly.com/question/15595203

4 0
2 years ago
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