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MakcuM [25]
3 years ago
5

Line segment Q R , Line segment R S and Line segment S Q are midsegments of Î"WXY. Triangle R Q S is inside triangle X Y W. Poin

t R is the midpoint of side X Y, point S is the midpoint of side Y W, and point Q is the midpoint of side X W. The length of Q R is 2. 93 centimeters, the length of R S is 2. 04 centimeters, and the length of Q S is 2. 28 centimeters. What is the perimeter of Î"WXY? 11. 57 cm 12. 22 cm 12. 46 cm 14. 50 cm.
Physics
1 answer:
Whitepunk [10]3 years ago
8 0

The perimeter of ΔWXY is : ( D ) 14.5 cm

<u>Calculating the </u><u>perimeter </u><u>of ΔWXY</u>

QR = WY / 2

RS = XW / 2

QS = XY / 2

Given that : QR = 2.93 cm ,  RS = 2.04 cm,  QS = 2.28 cm

Therefore

Perimeter of ΔWXY = ∑ WY + XW + XY  

                                 = 2SR + 2QS + 2QR

                                 = 2(2.04) + 2(2.28) + 2(2.93)

                                 = 14.5 cm

Hence we can conclude that the perimeter of ΔWXY = 14.5 cm

learn more about perimeter calculations : brainly.com/question/24744445

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Which type of mountain is created when rock layers are pushed up by forces inside the Earth?
skad [1K]

Correct answer choice is :


B) Upwarped


Explanation:


An upwarped mountain is a mountain consisting of a large area of the Earth's coat that has led smoothly upward without much visible deformation and normally including sedimentary, igneous, and metamorphic rocks. Sedimentary rocks are set down in layers called beds or layers. A bed is described as a layer of rock that has a similar lithology and character. Beds form by the removal of layers of sand on top of each other.

7 0
3 years ago
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A student connects an object with mass m to a rope with a length r and then rotates the rope around her head parallel to the gro
Alexandra [31]

The object takes 0.5 seconds to complete one rotation, so its rotational speed is 1/0.5 rot/s = 2 rot/s.

Convert this to linear speed; for each rotation, the object travels a distance equal to the circumference of its path, or 2<em>π</em> (1.2 m) = 2.4<em>π</em> m ≈ 7.5 m, so that

2 rot/s = (2 rot/s) • (2.4<em>π</em> m/rot) = 4.8<em>π</em> m/s ≈ 15 m/s

thus giving it a centripetal acceleration of

<em>a</em> = (4.8<em>π</em> m/s)² / (1.2 m) ≈ 190 m/s².

Then the tension in the rope is

<em>T</em> = (50 kg) <em>a</em> ≈ 9500 N.

7 0
3 years ago
How many total oxygen atoms are in the compound Molybdenum (V) Dichromate?
alekssr [168]

Answer:

1.2646\times10^{25}\ atoms

Explanation:

-The chemical formula for Molybdenum (V) Dichromate is Mo(Cr_2O_7)_3

-There are 21 moles of oxygen per one mole of Molybdenum (V) Dichromate

-We apply Avogadro's constant to find the number of atoms of oxygen:

Avogadro's \ Constant=6.022\times 10^{23} \ mol_1\\\\No\ of \ Atoms=Moles\times Avogadro's \ Constant\\\\=21\times 6.022\times 10^{23} \\\\=1.2646\times10^{25}\ atoms

Hence, there are 1.2646\times10^{25} \ atoms

3 0
4 years ago
An object with a mass of 25 kg object is moving at 30 m/s. What is the
Pani-rosa [81]

Answer: 750 kgm/s

Explanation:

Mass of object = 25 kg

Speed by which object moves =30 m/s. Linear momentum of the object = ?

Since momentum refers to the quantity of motion of the moving object,

Linear momentum = Mass x Speed

= 25kg x 30m/s

= 750 kgm/s

Thus, the linear momentum of the object is 750 kgm/s

7 0
4 years ago
9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o
Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).

Now the force of friction is F_s=\mu*N, where N is the normal force and from the diagram it is F_y=mg*cos(\theta).

Thus F_s=\mu*N=\mu*mg*cos(\theta).

Therefore,

F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).

Substituting the value for F_H,m,\mu, and \:\theta we get:

F_{tot}= -38.63N.

Now acceleration is simply

a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.

The negative sign indicates that the acceleration is directed up the incline.

Part B:

d=\frac{1}{2} at^2

Which can be rearranged to solve for t:

t=\sqrt{\frac{2d}{a} }

Substitute the value of d=0.50m and a=7.7m/s and we get:

t=0.36s.

which is our answer.

Notice that in using the formula to calculate time we used the positive value of a, because for this formula absolute value is needed.

5 0
4 years ago
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