We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
</span>- 1/(2-c)=-1/-(c-2)=1/(c-2)
(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)
(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14
the solution is c=14
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or
<span>all real numbers except c=-2 and c=2</span>
(4/9)/16 = 4/(9*16) = 4/(4*4*9) = 1/(4*9) = 1/36
One counter is
<span> if 16 of them are </span>
Answer:
Step-by-step explanation:
Standard form is Ax + By = C, so we want x to be on the left side
To accomplish this, subtract 1/4x from both sides.
Multiply by -4 to get x to be equal to 1.
Answer:
yes
Step-by-step explanation:
your answers are correct! congrats!
Im pretty sure its b im soo sorry if im wrong.
