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2 years ago

Is Figure A congruent to Figure B? Explain.

Mathematics

1 answer:

velikii [3]2 years ago

6 0

Yes, because figure B can be obtained from figure A by a series of translations

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A shoe store uses a 50% markup for all of the shoes it sells. What would be the selling price of a pair of shoes that has a who

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Answer:

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Step-by-step explanation:

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2 years ago

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5 more than the product of 9 and 3

dolphi86 [110]

(9)(3) + 5

27 + 5

32

Your answer is 32.

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3 years ago

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W+1/8 =8 plzz help me i need it

Marina CMI [18]

Answer:

w = 7 7/8

Step-by-step explanation:

w + 1/8 = 8

First, subtract 1/8 from both sides of the equation

w + 1/8 = 8

- 1/8 - 1/8

w = 7 7/8

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3 years ago

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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

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3 years ago

What is the area, in square feet, of the shape below? Express your answer as a fraction in simplest form.

Ahat [919]

4/3 • 5/3 = 20/9 divided by 2 = 10/9

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2 years ago