All categories

2 years ago

Laws of sines!!!!! find c. round to the nearest tenth!!!

Mathematics

2 answers:

nekit [7.7K]2 years ago

6 0

Answer:

c=0.5 cm

Step-by-step explanation:

Angle C is 15 and angle B is 105

The value of b=2cm

We need to find out 'a'

$\frac{sin A}{a} =\frac{sin B}{b} =\frac{sin C}{c}$

$\frac{sin B}{b} =\frac{sin C}{c}$

$\frac{sin 105}{2} =\frac{sin 15}{c}$

cross multiply it

$sin(105) c= sin(15) * 2$

Divide both sides by sin(105)

$c=\frac{sin(15)*2}{sin(105)}$

c=0.5

Mrac [35]2 years ago

5 0

Answer:

c = 0.5 cm

Step-by-step explanation:

Law of sines:

sin (15) / c = sin(105) / 2

0.2588 / c = 0.9659 / 2

c = 0.2588 * 2 / 0.9659

c = 0.5 cm

You might be interested in

Explain how to use the distributive property to find the product 3 x 4 1/5

NikAS [45]

Answer:

12.6

Step-by-step explanation:

The answer is 12.6 and here is the explanation of using the Distributive Property. Because we are multiplying a whole number by a mixed number, we have to multiply the whole number by the whole number in the mixed number and then multiply the whole number by the fraction. In this case, we have 3 x 4 1/5. We multiply 3x4=12 first, and then we multiply 3x1/5 to get 0.6. 12+0.6=12.6. Hope it helps!

5 0

3 years ago

Math:

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

7 0

3 years ago

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po

Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, $\sigma=0.2$ ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

$P(x\geq 10)=0.99$

Assume the bag weight distribution is bell-shaped

Therefore,

$P(\frac{x-\mu}{\sigma}\geq 10)=0.99$

We know that

$z=\frac{x-\mu}{\sigma}$

Using the value of z

Now,

$\frac{10-\mu}{0.2}=0.99$

$10-\mu=0.99\times 0.2$

$\mu=10-0.99\times 0.2$

$\mu=9.802$

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0

2 years ago

Select the correct product. (x + 8)(y + 3) xy + 8x + 3y + 24 xy + 3x + 8y + 24 11xy 24xy

MAXImum [283]

(x + 8)(y + 3)

x*(y+3) + 8*(y + 3)

x*y + 3*x + 8*y + 3*8

xy + 3x + 8y + 24

So the correct product is = xy + 3x + 8y + 24, I guess the second expression.

I hope this helps.

4 0

2 years ago

Read 2 more answers

Five less than twelve times a number is represented by:

Paraphin [41]

Option ( 1 )

.....................

5 0

3 years ago

Laws of sines!!!!! find c. round to the nearest tenth!!! ​

Laws of sines!!!!! find c. round to the nearest tenth!!!