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Likurg_2 [28]
3 years ago
10

A ball is thrown vertically upward from the top of a 96-ft tower, with an initial velocity of 16 ft/sec. Its position function i

s s(t) = -16t2 + 16t + 96. What is its velocity in ft/sec when it hits the ground?
Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

80 ft/s

Step-by-step explanation:

Given that,

A ball is thrown vertically upward from the top of a 96-ft tower, with an initial velocity of 16 ft/sec. Its position function is given by :

s(t)=-16t^2 + 16t + 96 ...(1)

When it hits the ground, s(t) = 0

-16t^2 + 16t + 96=0\\\\t=3\ s

At t = 3 s it will hit the fround.

We need to find its velocity when it hits the ground.

Differentiate equation (1) to find its velocity.

v=\dfrac{ds(t)}{dt}\\\\v=\dfrac{d(-16t^2 + 16t + 96)}{dt}\\\\v=-32t+16...(2)

Put t = 3 in equation (2)

v=-32(3)+16\\\\v=-80\ ft/s

Hence, when it will ground its velocity is 80 ft/s.

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tatiyna

Answer:

b_{1}=\frac{2A}{h}-b_{2}

Step-by-step explanation:

Given: A=\frac{1}{2}(b_{1} +b_{2})h

We need to completely isolate b_{1} to solve.

A=\frac{1}{2}(b_{1} +b_{2})h

A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h

A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}

Finally, multiply both sides by -2 to completely isolate b_{1}.

b_{1}=\frac{2A}{h}-b_{2}

5 0
3 years ago
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Answer:

6 knots

Step-by-step explanation:

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d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve

so setting dF/dv will give a minima

500[ -216/v^2 + v] = 0

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a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d, and e are not zero

 

PROVE

 a/b * b/c * c/d * d/e

= (a/b *b/c) * (c/d * d/e)

= ab/bc * (c/d * d/e)

= a/c * (c/d * d/e)

= a/c * (cd/de)

= a/c * c/e

= ac/ce

= a/e

 

Therefore, a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d, and e are not zero

7 0
3 years ago
write the equation if the line in slope- intercept form that passes through (7,-4) with a slope of -1.
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9514 1404 393

Answer:

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The point-slope form can be a useful place to start.

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You require the line ...

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  y = -x +7 -4 . . . . . . . . eliminate parentheses, add -4

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