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tensa zangetsu [6.8K]
3 years ago
11

Given the Formula E equals IR what is the formula R

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

sup

Step-by-step explanation:

scZoUnD [109]3 years ago
5 0
E = IR
R = E/I

You have to divide I form R
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I got this question wrong on a warm-up in class and I'm doing error analysis. Can someone solve this and explain why? I'm giving
Studentka2010 [4]

Answer:

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2 years ago
Please help me solve the table below
ArbitrLikvidat [17]

Answer:

2, 4 ,6 8

Step-by-step explanation:

Given condition y = 2x

When x = 1 , y = 2 *1 = 2

When x = 2 , y = 2 * 2= 4

when x = 3 , y = 2* 3 = 6

When x = 4 , y = 2 * 4 = 8

Hope it will help :)

5 0
3 years ago
Write a system of equations for the following situation:
wariber [46]

Answer: B) a + c = 10

8a + 5c = 59

Step-by-step explanation:

We know that 10 total people went, so the first equation has to be equal to 10. The total was $59, so the second equation should be set equal to $59. Now that the second equation is for cost, we must make it 8a + 5c to represent the cost of the adult and child tickets which are $8 and $5, respectively.

5 0
3 years ago
Read 2 more answers
A man bought 42 stamps, some 13¢ and some 18¢. How many of each kind did he buy if the cost was $6.66?
Andrews [41]

The system of equation which represent the scenario is;

x + y = 42

x + y = 420.13x + 0.18y = 6.66

<h3>Simultaneous equation</h3>

let

  • number of 13 cent stamps = x
  • number of 18 cent stamps = y
  • Total cost of the stamps = $6.66
  • Total number of stamps = 42

x + y = 42

x + y = 420.13x + 0.18y = 6.66

Therefore, the equation which represent the problem is;

x + y = 42

0.13x + 0.18y = 6.66

Learn more about simultaneous equation:

brainly.com/question/16863577

#SPJ1

3 0
2 years ago
At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more
I am Lyosha [343]

Answer:

The probability is  P( X \le 4 ) = 0.0054

Step-by-step explanation:

From the question we are told that

   The percentage that are on time is  p =  0.76

   The  sample size is n =  11

   

Generally the percentage that are not on time is

     q =  1- p

     q =  1-  0.76

     q = 0.24

The  probability that no more than 4 of them were on time is mathematically represented as

        P( X \le 4 ) =  P(1 ) +  P(2) + P(3) +  P(4)

=>     P( X \le 4 ) =  \left n } \atop {}} \right.C_1 p^{1}  q^{n- 1} +   \left n } \atop {}} \right.C_2p^{2}  q^{n- 2} +  \left n } \atop {}} \right.C_3 p^{3}  q^{n- 3}  +  \left n } \atop {}} \right.C_4 p^{4}  q^{n- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{11- 1} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{11- 2} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{11- 3}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{11- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{10} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{9} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{8}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{7}

= \frac{11! }{ 10! 1!}  (0.76)^{1}  (0.24)^{10} +   \frac{11!}{9! 2!}  (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!}  (0.76)^{3}  (0.24)^{8}  + \frac{11!}{7!4!}  (0.76)^{4}  (0.24)^{7}

P( X \le 4 ) = 0.0054

4 0
3 years ago
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