Answer:
2nd choice B.
Step-by-step explanation:
You can use the options A-D to help you eliminate pretty quickly without actually graphing
So first chose says you have the graph on the left when x<1 But you should see our visual actually says we want to include what happens at 1 (the filled dot) so this isn't the answer
Second choice Possible
Third choice... I'm just going to look at one of the parts... x^2+4 for x<=1 says we should have part of a parabola to the left of x=1 (inclusive) but there is not parabola in our visual
Fourth choice: same reason as third choice
Answer is the 2nd
Answer:
fhvb4bhfbrhjbf57428526t825
Step-by-step explanation:
Answer:
5.625 pints
Step-by-step explanation:
refer to pic
Answer:
See explanation
Step-by-step explanation:
1. The given function is

The domain values are: x=0, 2, -1, 4, -2
When x=0

When x=2,

When x=-1

When x=4

When x=-2

2. The given function is

When x=3,

Similarly,




Y =ax² + bx +c
1) Point (0,7)
7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7
2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------>
a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ---->
-1=2a + b
4)
a+b= - 3, ----> b= -3 - a (substitute in the second equation)
2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1,
a =2
5) a+b= - 3
2 + b = -3
b = -5
y=2x² - 5x + 7