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Tcecarenko [31]
3 years ago
13

a triangle has an area of 54 m2 and a height of 9m how long is the base of the triangle entered your answer in the box

Mathematics
2 answers:
Delvig [45]3 years ago
7 0
Answer:
base of the triangle = 12 m

Explanation:
Area of the triangle = 1/2 * base * height
We are given that:
area = 54 m^2
height = 9 m

Substitute in the equation to get the base as follows:
Area of the triangle = 1/2 * base * height
54 = 1/2 * base * 9
108 = 9*base
base = 12 m

Hope this helps :)
zhannawk [14.2K]3 years ago
6 0
The first thing you should know to solve this problem is that the definition of the area of the triangle is:
 A =(1/2)* b * h
 Where,
 b: base
 h: height.
 Clearing the base we have:
 b = 2*A / h
 Substituting the values
 b = 2*(54) / (9) = 12 m
 Answer:
 The base of the triangle is 12m long
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Find the missing angels in the parallelogram
krek1111 [17]

Answer:

m<B = 60°

m<C = 60°

m<F = 80°

m<G = 80°

Step-by-step explanation:

m<B = 180° - 120° = 60°

m<C = m<B = 60° (Vertically opposite angles are equal)

m<F = 180° - (40° + m<C(60°)) = 80°

m<G = 180° - (m<H + m<B) = 180° - (40° + 60°) = 80°


6 0
3 years ago
2(1 - 3y) - 13x ik the answer idk how to show the work plz help KEY: y = -9 x = 4
AURORKA [14]

Answer:

The answer is 4.

Step-by-step explanation:

2(1 - 3y) - 13x

2(1−(3)(−9))−(13)(4)

56-52

=4

4 0
3 years ago
I will mark brainliest if correct please answer fast I will give 10 points to the first person who answers
attashe74 [19]

Answer:

99\ in^{2}

Step-by-step explanation:

Area of any triangle could be always calculated as base length multiplied by the height perpendicular to the aforementioned base divided by 2. Therefore:

A = 18 * 11 / 2 = 198 / 2 = 99

4 0
3 years ago
A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate
neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:  

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate  munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

C-2=\frac{1}{11}*(C+D-2)...(1)

We are also told if he instead added 4  glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

C=\frac{1}{7}*(C+D+4)...(2)

Upon substituting C's value from equation (2) in equation (1) we will get,

\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)

Let us have a common denominator on right side of equation.

\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)

\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)

Multiplying both sides of our equation by 7, we will get,

7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)

C+D-10=\frac{7}{11}*(C+D-2)  

Multiplying both sides of our equation by 11, we will get,

11*(C+D-10)=11*\frac{7}{11}*(C+D-2)  

11*(C+D-10)=7*(C+D-2)

11C+11D-110=7C+7D-14

11C-7C+11D-7D=-14+110  

4C+4D=96

4(C+D)=96  

(C+D)=\frac{96}{4}

(C+D)=24

Therefore, the total number of Munchkins in original box is 24.

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4.29484728283
The number are repeated forever is not rational number
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3 years ago
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