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andriy [413]
3 years ago
10

Can some one help me with this question its hard :( down below ill give brainliest

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

B) 7^2 x 7^3

Step-by-step explanation:

B is 7^5 , everything else is 7^4

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Determine the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1) by following the steps below.
GaryK [48]

Answer:

Radius length: √5

Standard Form (Equation): (x + 4)^2 + y^2 = 5

Step-by-step explanation:

First we will determine the radius;

Center: (-4, 0)

Point on Circumference: (-2, 1)

d = √(-2 - (-4))^2 + (1 - 0)^2 = √(2)^2 + (1)^2

= √4 + 1 = √5

Therefore the radius is of length √5

Now the equation of a circle is in the form ((x - h)^2 + (y - k)^2) = r^2. The center is in the form (h,k) and r is the radius. Given this our equation would be (x - (-4))^2 + (y - 0)^2 = (√5)^2, or [simplified] (x + 4)^2 + y^2 = 5.

6 0
2 years ago
Read 2 more answers
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