For this case we have the following data:
Polynomial function of grade 5
Given roots: -2, 2,
Having an imaginary root given by 
, the other root, in the same imaginary way, must be given by its complex conjugate, that is, 
.
In this way, the fourth root is given by:
Since the polynomial function is grade 5, it must have 5 roots. Thus, the fifth root must be given by a real number.
Thus, the roots of the polynomial function are given by: three real roots and two imaginary roots.
Answer:
Option D
Answer:
the 0
Step-by-step explanation:
Well i got -19/6 but if you simplify it it would be -3.16667
Answer:
y=-5, x=13
Step-by-step explanation:
y value equals -5, plug that value into the other problem and solve
Hello :
<span>y = –2x² +6x – 1.
y = -2(x²-3x)-1
y= -2( x² -2(3/2)x +(3/2)² - </span>(3/2)²)-1
y = -2((x-3/2)² -9/4))-1
y = -2(x-3/2)² +7/2
the <span>axis of symmetry is the line : x = 3/2 and vertex : (3/2 , 7/2 ) </span>
