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Tanzania [10]
3 years ago
5

PLEASE HELP WITH STEP BY STEP I NEED TO SHOW MY WORK I GO BACK TO CLASS IN 6 MINS

Mathematics
2 answers:
LekaFEV [45]3 years ago
8 0

Answer:

4920

Step-by-step explanation:

=(8×600)+(8×10)+(8×5)

=(4800)+(80)+(40)

=4920

eduard3 years ago
6 0
8 x 615 is 4920.

615
x. 8

______

put a 4 above the one and a 1 above the 6.
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REWARDING BRAINLY TO CORRECT ANSWER
alexandr402 [8]

Answer:

41

Step-by-step explanation:

20, 22, 23, 23, 26, 27, 34

175/7=25

175+x/8=27

175+x=216

x= 41

8 0
3 years ago
Read 2 more answers
What is the approximate volume of a cylinder with a height of 2 ft and a radius of 6 ft? Use 3.14 to approximate pi. Express you
Keith_Richards [23]
Your answer would be an almighty

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It would be 226.08ft^3
8 0
3 years ago
Please I really need help!Please show your work :)​
Anettt [7]

Answer:

50 stars

Step-by-step explanation:

1 × 50 is 50 so you get 50 stars

8 0
4 years ago
A piece of wire of length 5050 is​ cut, and the resulting two pieces are formed to make a circle and a square. Where should the
algol [13]

Answer:

x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

Step-by-step explanation:

Let x be the length of wire that is cut to form a circle within the 5050 wire, so 5050 - x would be the length to form a square.

A circle with perimeter of x would have a radius of x/(2π), and its area would be

A_c = \pir^2 = \pi (\frac{x}{2pi})^2 = \frac{x^2}{4\pi}

A square with perimeter of 5050 - x would have side length of (5050 - x)/4, and its area would be

A_s = (\frac{5050 - x}{4})^2 = \frac{(5050 - x)^2}{16}

The total combined area of the square and circles is

\sum A = A_c + A_s = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}

To find the maximum and minimum of this, we just take the 1st derivative, and set it to 0

A' = \frac{2x}{4\pi} + \frac{-2(5050-x)}{16} = 0

\frac{x}{2\pi} - \frac{5050 - x}{8} = 0

Multiple both sides by 8π and we have

4x - 5050\pi + x\pi = 0

x(4 + \pi) = 5050\pi

x = \frac{5050\pi}{4 + \pi} = 2221.5

At x = 2221.5:

A = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16} = 392720 + 500026 = 892746 [/tex]

At x = 0, A = 5050^2/16 = 1593906

At x = 5050, A = \frac{5050^2}{4\pi} = 2029424

As 892746 < 1593906 < 2029424, x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

3 0
3 years ago
Please do number 23.
liraira [26]

Answer:

  165

Step-by-step explanation:

Let o and b represent the numbers of orchestra and balcony tickets bought, respectively.

  o + b ≥ 250 . . . . at least 250 tickets will be bought

  o = b - 80 . . . . .  there will be 80 fewer orchestra than balcony bought

Substituting for o, we have ...

  (b -80) +b ≥ 250

  2b ≥ 330 . . . . . . . add 80

  b ≥ 165 . . . . . . . . .divide by 2

The least number of balcony tickets the club could buy is 165.

5 0
4 years ago
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