Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48
Answer:
7.2 + 0.8w
Step-by-step explanation:
combine like terms. Like terms have same variable with same power.
2.2w and (-1.4w) are like terms & 4.8 and 2.4 are like terms.
4.8 + 2.2w - 1.4w + 2.4 = 4.8 + 2.4 + 2.2w - 1.4w
= 7.2 + 0.8w
Answer:
<u>81920</u>
Step-by-step explanation:
Finding the common ratio (r) :
Finding the 14th term :
- a₁₄ = ar¹⁴⁻¹
- a₁₄ = ar¹³
- a₁₄ = (10)(2)¹³
- a₁₄ = (10)(8192)
- a₁₄ = <u>81920</u>
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
<span>Answer: the third option (12 zeroes..). </span>
<span>Use ^ to denote an exponent.. </span>
<span>f(x) = 3x^12 - 17x^8 + 11x^4 - 6x + 23.. </span>
<span>We know from that fact that the number of zeroes (real or complex) in a polynomial is the same as the degree of the polynomial.. </span>
<span>The degree is the greatest/highest power of the terms, which in this case is 12 (since 12 is the greatest exponent..).. </span>
<span>The degree is 12, thus it means there are 12 zeroes.. </span>
<span>Answer: the third option (12 zeroes)...</span>
