Question

A point is chosen at random on AK. What is the probability that the point will be on overline CD ? Don't forget to reduce.

Answer 1

Answer:

$P(CD) = \frac{1}{10}$

Step-by-step explanation:

Given

$AK = 10$

See attachment for line AK

Required

Probability of choosing CD

From the attachment:

$CD=D-C$

$CD=3 - 2$

$CD = 1$

So:

$P(CD) = \frac{CD}{AK}$

$P(CD) = \frac{1}{10}$