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andre [41]
3 years ago
9

A point is chosen at random on AK. What is the probability that the point will be on overline CD ? Don't forget to reduce.

Mathematics
1 answer:
Elena L [17]3 years ago
8 0

Answer:

P(CD) = \frac{1}{10}

Step-by-step explanation:

Given

AK = 10

See attachment for line AK

Required

Probability of choosing CD

From the attachment:

CD=D-C

CD=3 - 2

CD = 1

So:

P(CD) = \frac{CD}{AK}

P(CD) = \frac{1}{10}

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8 0
3 years ago
2/3x - 1/2y = 3
Makovka662 [10]
The correct answer for this question would be the second option. <span>4x - 3y = 18 and x + 2y = 10. So in order to know why this is the answer, let us check it. Since the given numbers have fractions, let us eliminate the fractions.
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Next,
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3 0
3 years ago
Read 2 more answers
2x-7/3=1 please answer my question iwill mark brainliest
Neporo4naja [7]

2x -  \frac{7}{3}  = 1 \\  \\ 2x = 1 +  \frac{7}{3}  \\  \\ 2x =  \frac{3 + 7}{3}  \\  \\ 2x =  \frac{10}{3}  \\  \\ x =  \frac{5}{3}  \\  \\ x = 1 +  \frac{2}{3}  \\  \\ x = 1 + 0.66666 \\  \\ x = 1.66666

3 0
4 years ago
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HELP ASAP
almond37 [142]

Answer:

Step-by-step explanation:

let the number of dimes=x

and number of quarters=y

x=2y

0.10 x+0.25 y=2.25

or 10x+25y=225

divide by 5

2x+5y=45

2 ×2y+5y=45

4y+5y=45

9y=45

y=45/9=5

x=2y=2×5=10

Hence dimes=10

quarters=5

6 0
4 years ago
Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa
KengaRu [80]

Answer:

a. <u>0.5 or 50%</u>

b. <u>0.496 or 49.6%</u>

c. <u>0.8185 or 81.85%</u>

d. <u>Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm</u>

e. <u>0.0252 or 2.52%</u>

f. <u>The qualifying speed would be 47.4 wpm.</u>

Step-by-step explanation:

a. Let's find the z-score this way:

μ  = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

<u>p (z=0) = 0.5 or 50%</u>

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

<u>p (z = -0.01) = 0.496 or 49.6%</u>

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

c.

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

<u>In consequence,</u>

<u>p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%</u>

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

<u>Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.</u>

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

<u>p = 0.0252 or 2.52%</u>

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

<u>The qualifying speed would be 47.4 wpm.</u>

8 0
3 years ago
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