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andre [41]
3 years ago
9

A point is chosen at random on AK. What is the probability that the point will be on overline CD ? Don't forget to reduce.

Mathematics
1 answer:
Elena L [17]3 years ago
8 0

Answer:

P(CD) = \frac{1}{10}

Step-by-step explanation:

Given

AK = 10

See attachment for line AK

Required

Probability of choosing CD

From the attachment:

CD=D-C

CD=3 - 2

CD = 1

So:

P(CD) = \frac{CD}{AK}

P(CD) = \frac{1}{10}

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Which equation shows the result of substituting and expression for y from the first equation into the second equation for the gi
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x-2x = -3 and x = 3

Step-by-step explanation:

Given the expression

y=x+5.... 1

y-2x=2.... 2

Substituting the first equation into the second we will have;

From 2;

y -2x = 2

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Hence the required equation is x-2x = -3 and x = 3

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Complete the input-output table for the function y = 3x.<br><br> Input-Output table
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Answer:

Y: 0, x:0

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Y: 2, x: 6

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Step-by-step explanation:

Plug in the x to get the y

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3 years ago
A coin is tossed 8 times. What is the probability of getting all heads? Express your answer as a simplified fraction or a decima
kumpel [21]

Answer:

The probability of getting all heads is \frac{1}{256}.

Step-by-step explanation:

For each time the coin is tossed, there are only two possible outcomes. Either it is heads, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

A coin is tossed 8 times. This means that n = 8

In each coin toss, heads or tails are equally as likely. So p = \frac{1}{2}

What is the probability of getting all heads?

This is P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

[tex]P(X = 8) = C_{8,8}*(\frac{1}{2})^{8}*(1 - \frac{1}{2})^{0} = \frac{1}{256}

The probability of getting all heads is \frac{1}{256}.

7 0
3 years ago
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