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Eddi Din [679]
2 years ago
13

What is the value of x^6+y^2x 6 +y 2 x, start superscript, 6, end superscript, plus, y, squared when x=1x=1x, equals, 1 and y=11

y=11y, equals, 11?
Mathematics
2 answers:
Scrat [10]2 years ago
8 0

Try 122.

<h3 />

Step-by-step explanation:

Since <em>x</em> = 1, x^6 = 1.

Since <em>y</em> = 11, 11^2 = 121.

1 + 121 = 122.

<h3 /><h3>So, the value of <em>x</em> ^ 6 + <em>y </em>^ 2 = 122.</h3><h3 />
Lemur [1.5K]2 years ago
8 0

Answer:

122

Step-by-step explanation:

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