What is the value of x^6+y^2x 6 +y 2 x, start superscript, 6, end superscript, plus, y, squared when x=1x=1x, equals, 1 and y=11 y=11y, equals, 11?
2 answers:
Try 122.
<h3 />
Step-by-step explanation:
Since <em>x</em> = 1, x^6 = 1.
Since <em>y</em> = 11, 11^2 = 121.
1 + 121 = 122.
<h3 /><h3>
So, the value of <em>
x </em>
^ 6 + <em>
y </em>
^ 2 = 122. </h3><h3 />
Answer:
122
Step-by-step explanation:
You might be interested in
Answer:
2280 kcal
Step-by-step explanation:
The given function R(t) is periodic with a period of 24 hours, so the integral is the product of the average value (95 kcal/h) and the 24-hour interval:
(95 kcal/h)(24 h) = 2280 kcal
Answer:
-3t ≥39
-3t/-3 ≥39/-3
t≤-13
The answer to this is
Answer:
7 6/7
Step-by-step explanation:
V=(1/3)hπr^2 where h=height and r=radius
