What is the value of x^6+y^2x 6 +y 2 x, start superscript, 6, end superscript, plus, y, squared when x=1x=1x, equals, 1 and y=11
y=11y, equals, 11?
2 answers:
Try 122.
<h3 />
Step-by-step explanation:
Since <em>x</em> = 1, x^6 = 1.
Since <em>y</em> = 11, 11^2 = 121.
1 + 121 = 122.
<h3 /><h3>
So, the value of <em>
x</em>
^ 6 + <em>
y </em>
^ 2 = 122.</h3><h3 />
Answer:
122
Step-by-step explanation:
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Step-by-step explanation:
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