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Eddi Din [679]
3 years ago
13

What is the value of x^6+y^2x 6 +y 2 x, start superscript, 6, end superscript, plus, y, squared when x=1x=1x, equals, 1 and y=11

y=11y, equals, 11?
Mathematics
2 answers:
Scrat [10]3 years ago
8 0

Try 122.

<h3 />

Step-by-step explanation:

Since <em>x</em> = 1, x^6 = 1.

Since <em>y</em> = 11, 11^2 = 121.

1 + 121 = 122.

<h3 /><h3>So, the value of <em>x</em> ^ 6 + <em>y </em>^ 2 = 122.</h3><h3 />
Lemur [1.5K]3 years ago
8 0

Answer:

122

Step-by-step explanation:

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The equation of the line of best fit is y=3x+2. x=the number of ice cream sales and y= the number of days. Answer the following
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Answer:

all I know is how to get y but y=122

Step-by-step explanation:

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Step-by-step explanation:

Here,

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andreev551 [17]

Answer:

p_v =P(t_{74}    

If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation    

\bar X=18.81 represent the average lateral recumbency for the sample    

s=8.4 represent the sample standard deviation    

n=75 sample size    

\mu_o =20 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a left tailed  test.  

What are H0 and Ha for this study?    

Null hypothesis:  \mu \geq 20  

Alternative hypothesis :\mu < 20  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227

The degrees of freedom are given by:

df=n-1=75-1=74    

Give the appropriate conclusion for the test  

Since is a one side left tailed test the p value would be:    

p_v =P(t_{74}    

Conclusion    

If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

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