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Vera_Pavlovna [14]
3 years ago
8

Jeremy mowed several lawns to earn money for camp. After he paid $17 for gas, he had $75 leftover to pay towards camp. Write and

solve an equation to find how much money Jeremy earned mowing lawns.
Mathematics
1 answer:
Alexxx [7]3 years ago
6 0
Money earned = ee=75+17=92
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What is the total amount that Mathews bank will receive after lending him 8000 for four years
marysya [2.9K]

Answer:

32,000

Step-by-step explanation:

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3 years ago
If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –
sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is 5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5

<h3>To find the value of x :</h3>

First solving the given equation we have,

5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5

5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5

20\times (2)^{2-3x}=10\times (2)^{-2x}

20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}

20\times 4.(2)^{-3x}=10\times (2)^{-2x}

80(2)^{-3x}=10\times (2)^{-2x}

\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}

8(2)^{-3x}=(2)^{-2x}

\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}

(2)^{-3x}.(2)^{2x}=\frac{1}{2^3} ( by using the property \frac{1}{a^{-m}}=a^m )

2^{-3x+2x}=\frac{1}{2^3} ( by using the property a^m.a^n=a^{m+n} )

2^{-x}=\frac{1}{2^3}

\frac{1}{2^x}=\frac{1}{2^3} ( by using the property a^{-m}=\frac{1}{a^m} )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>
5 0
3 years ago
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Evaluate 29 -6 × 3.
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The answer to your questions is 11 because PEMDAS. () exponents multipication division addition and subtraction. 
8 0
3 years ago
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Simplify the product –8(–9) <br> A.71<br> B.74<br> C.72<br> D.70
Fittoniya [83]

Answer:

the answer is 72....

- × - = +

5 0
3 years ago
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1/3k+80=1/2k+120 what does k equal?
LenaWriter [7]

Answer:

k = -1/240

Step-by-step explanation:

to evaluate the value of k in the expression 1/3k+80=1/2k+120

we have

1/3k+80=1/2k+120

collect the like terms for easy evaluation

1/3k - 1/2k = 120 -80

1/3k - 1/2k = 40

find the lcm

2 - 3/6k = 40

-1/ 6k = 40

cross multiply

6k  x  40  = -1

240k = -1

divide both sides by 240

240k/240 = -1/ 240

k = -1/240

therefore the value of k in the expression 1/3k+80=1/2k+120 is equals to -1/240

8 0
3 years ago
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