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2 years ago

(MATH) (6) ((PHOTO))label is sq yd

Mathematics

1 answer:

Annette [7]2 years ago

5 0

Answer:

Step-by-step explanation:

To find the total amount of sq yd's of paint needed, you have to find the area.

The area of a triangle is: A = 1/2 bh

We know:

b = base = 8

h = height = 5

Plug in and solve:

A = 1/2 (8) (5)

A = 1/2 (40)

A = 20

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Find the equivalent to x^7

MrMuchimi

1/x^-7

It would look more like 1
------
-7 (as an exponent)
x

3 0

2 years ago

Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f

GalinKa [24]

Answer:

$\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }$

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

$\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}$

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

$f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240$

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in $\mathbb{R}$ .

$\\f(x)=(x^2+16)(x^2-2x-15)$

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

$f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}$

And we can write in $\mathbb{C}$

$f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0

2 years ago

Please help i dont understand

Roman55 [17]

Your answer would be 46.50 because you would divide 31 in half (for the 50%) then add that to the 31. So 31+15.50= $46.50 hope this helps. If not let me know

7 0

2 years ago

the polynomial 3x+5 is divided by x+2 what is the quotient, pls be quick im taking a algebra progress check due in 25 min

il63 [147K]

Answer:

The quotient of the rational function is $3 -\frac{1}{x+2}$ .

Step-by-step explanation:

We proceed to solve the expression by solely algebraic means below:

1) $\frac{3\cdot x + 5}{x+2}$ Given

2) $\frac{(3\cdot x + 5) + 0}{x + 2}$ Modulative property

3) $\frac{(3\cdot x +5) + [1+(-1)]}{x+2}$ Existence of additive inverse/Associative property

4) $\frac{(3\cdot x + 6)+(-1)}{x+2}$ Definition of addition/Commutative and associative properties

5) $\frac{3\cdot (x+2)}{x+2} + \left(-\frac{1}{x+2} \right)$ $\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}$ / $\frac{-a}{b} = \frac{a}{-b} = -\frac{a}{b}$ /Distributive property