All categories

3 years ago

Warren has a container which holds 22 books of the same shape and size. The exact breakdown of his books is shown below:

Mathematics

1 answer:

ohaa [14]3 years ago

7 0

Given:

Total number of book = 22

Number of white books = 6

Number of Purple books = 9

Number of green books = 7

To find:

The probability that Warren takes out a green book in both draws (with replacement).

Solution:

We know that,

$\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

$P(\text{White})=\dfrac{6}{22}$

$P(\text{Purple})=\dfrac{9}{22}$

$P(\text{green})=\dfrac{7}{22}$

After replacement, the probability of event remains the same and the independent.

The probability that Warren takes out a green book in both draws is:

$P=P(\text{green})\times P(\text{green})$

$P=\dfrac{7}{22}\times \dfrac{7}{22}$

$P=\dfrac{49}{484}$

Therefore, the correct option is (a).

You might be interested in

Find the probability that when a fair coin is flipped four times at least 2 heads

salantis [7]

Since the problem states "at least" we need to also find probability of 3 H or 4 H or 5 H

Now find the probability of flipping a head 4 times; $\frac{1}{2}$ ⁴
= (1/16)

Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16

Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16

(1/16)+(4/16)+(6/16)=11/16

Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.

Hope I helped :)

8 0

3 years ago

Pls help answer this

Paladinen [302]

Answer: Third option

Step-by-step explanation:

For this exercise it is important to remember the following:

1. By definition, the Associative property of addition states that it does not matter how you grouped the numbers, you will always obtained the same sum.

2. The rule for the Associative property of addition is the following (given three numbers "a", "b" and "c"):

$a + (b + c) = (a + b) + c$

Knowing the information shown before, you can identify in the picture attached that the option that illustrates the Associative property of addition is the third one. This is:

$(11+8)+1=11+(8+1)$

As you can notice that you will always get the same result:

$(19)+1=11+(9)\\\\20=20$

8 0

3 years ago

A computer program contains one error. In order to find the error, we split the program into 6 blocks and test two of them, sele

Aleksandr-060686 [28]

There are $\dbinom62$ ways of selecting two of the six blocks at random. The probability that one of them contains an error is

$\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13$

So $X$ has probability mass function

$f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}$

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.

The expected value of finding an error is then

$\displaystyle\sum_{x=0}^1xf_X(x)=0\times\dfrac23+1\times\dfrac13=\dfrac13$