Question

Warren has a container which holds 22 books of the same shape and size. The exact breakdown of his books is shown below:

Answer 1

Given:

Total number of book = 22

Number of white books = 6

Number of Purple books = 9

Number of green books = 7

To find:

The probability that Warren takes out a green book in both draws (with replacement).

Solution:

We know that,

$\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

$P(\text{White})=\dfrac{6}{22}$

$P(\text{Purple})=\dfrac{9}{22}$

$P(\text{green})=\dfrac{7}{22}$

After replacement, the probability of event remains the same and the independent.

The probability that Warren takes out a green book in both draws is:

$P=P(\text{green})\times P(\text{green})$

$P=\dfrac{7}{22}\times \dfrac{7}{22}$

$P=\dfrac{49}{484}$

Therefore, the correct option is (a).