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3 years ago

Find the missing angle: e.

Mathematics

1 answer:

sattari [20]3 years ago

8 0

Answer: e = 33

Keep referring to the picture to understand which part of the figure I am talking about.

Step-by-step explanation:

So starting from the top triangle, one of the angles are 34 and the triangle looks like an Isosceles (a triangle that has 2 equal angles and sides). So to find the other 2 angles you have to take away the already given angle from 180 (as all angles in a triangle add up to 180 degrees) and divide it by 2. So- 180 - 34 = 146.

146 ÷ 2 = 73- angle of each of the remaining 2 sides.

The left side of that triangle is extended to be part of the quadrilateral (the four sided figure with angle e). So to now solve the top left angle of the quadrilateral which is connected to the triangle you have to takeaway the angle which is part of the triangle from 180 (Angles on a line add to 180) So-

180 - 73 = 107 - angle for the top left part of the quadrilateral.

To find the 3rd angle on the bottom right, you need to solve the angles of the bottom triangle connected to it. Use the same method I have shown for the top triangle as the triangle look like an Isosceles like the other one -

180 - 30 = 150

150 ÷ 2 = 75- angle of each of the remaining 2 sides

Coming back to finding the 3rd angle, you have to use the line at the bottom where you found one of angles now. Use the same angles on the same line rule used before-

180 - 75 = 105- angle for the bottom right of the quadrilateral

You now have all the angles in the quadrilateral except for e which you will find by adding up all the known angles in the quadrilateral and take it away from 360 (all angles in a quadrilateral add to 360) So-

115 + 107 + 105 = 327

360 - 327 = 33

Therefore e = 33

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A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

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Answer:

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So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

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