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elena-14-01-66 [18.8K]
4 years ago
4

At STP, oxygen exists in two forms, O2(g) and O3(g). These two forms of oxygen have 1. different molecular structures and differ

ent properties 2. different molecular structures and the same properties 3. the same molecular structure and different properties 4. the same molecular structure and the same properties
Chemistry
2 answers:
KiRa [710]4 years ago
6 0
At STP, oxygen exists in two forms, O2(g) and O3(g). These two forms of oxygen have <span>different molecular structures and different properties. The answer is number 1. The rest of the numbers do not answer the question above.</span>
marin [14]4 years ago
5 0

Answer: option 1. different molecular structures and different properties.

Explanation:

1) O₂ and O₃ are different forms of the same element, in the same physical state (gaseous).

2) That is what is called allotropes.

3) The definition of allotropes is different forms of an element with different structures and different properties in the same physical state.

Graphite and diamond is other example of common allotropes.

4) O₃ and O₂ have the same kind of atoms (oxygen), but they are bonded differently (different structure, one molecule has 3 atoms, other 2 atoms) which conferes them different properties (e.g. different odor, different chemical reactivity).

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Please Help!!
Leokris [45]

Answer: The covalent bonds within a molecule are very (strong). However it requires (less) energy to melt a molecular compound than an ionic compound.

This is because the attractive forces between individual molecules are (weaker) than the forces between ions in an ionic compound.

6 0
3 years ago
Read 2 more answers
When testing water for chemical impurities, results are often reported as BDL, that is, below detection limit. The following are
Mumz [18]

Answer:

The median level in the water is 7ppm

Explanation:

LoB is assessed by calculating duplicates of a blank sample and evaluating the mean result and the standard deviation (SD). After evaluating this value LOD can be evaluated conferring to LOD=LOB+1.645(SD low concentration sample ). The quantitation limit can also be got from accuracy studies. LOD's may also be evaluated based on the standard deviation of the response (Sy) of the curve and the slope of the calibration curve (S) at levels resembling the LOD according to the formula: LOD = 3.3\frac{Sy}{S}

4 0
3 years ago
Water can be used to create electricity. This type of energy is called _____.
LUCKY_DIMON [66]
It is hydroelectric power
4 0
4 years ago
Read 2 more answers
Calculate the maximum volume in ml of 0.15M HCl that each of the following antacid formulations would be expected to neutralize.
vlada-n [284]

a. 34 mL; b. 110 mL

a. A tablet containing 150 Mg(OH)₂


Mg(OH)₂ + 2HCl ⟶ MgCl₂ + 2H₂O


<em>Moles of Mg(OH)₂</em> = 150 mg Mg(OH)₂ × [1 mmol Mg(OH)₂/58.32 mg Mg(OH)₂

= 2.572 mmol Mg(OH)₂


<em>Moles of HCl</em> = 2.572 mmol Mg(OH)₂ × [2 mmol HCl/1 mmol Mg(OH)₂]

= 5.144 mmol HCl


Volume of HCl = 5.144 mmol HCl × (1 mmol HCl/0.15 mmol HCl) = 34 mL HCl


b. A tablet containing 850 mg CaCO₃


CaCO₃ + 2HCl ⟶ CaCl₂ + CO₂ + H₂O


<em>Moles of CaCO₃</em> = 850 mg CaCO₃ × [1 mmol CaCO₃/100.09 mg CaCO₃

= 8.492 mmol CaCO₃


<em>Moles of HCl</em> = 8.492 mmol CaCO₃ × [2 mmol HCl/1 mmol CaCO₃]

= 16.98 mmol HCl


Volume of HCl = 16.98 mmol HCl × (1 mL HCl/0.15 mmol HCl) = 110 mL HCl


5 0
3 years ago
Hi! I could use some help, I need to turn this in today
TiliK225 [7]

Explanation:

The nomenclature of ionic compounds is given by:

1. Positive is written first.  And if the metal atom has various oxidation states then its oxidation state is to be mentioned in brackets with help of roman numbers

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

1.)  : Calcium chloride  (Correct)

In the given compound, calcium has oxidation state of +2 and chlorine has oxidation state of -1.The name is correct.

2.)  : Copper (II) oxide   (Incorrect)

In the given compound,copper has the oxidation state of +1 and oxygen has oxidation state of -2.So ,the correct name will be Copper (I) oxide.

3.)  : Lead (II) sulfide   (Incorrect)

In the given compound, lead has the oxidation state of +4 and sulfur has oxidation state of -2. So ,the correct name will be Lead (IV) sulfide.

3 0
3 years ago
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