Answer:
A = 1,13x10¹⁰
Ea = 16,7 kJ/mol
Explanation:
Using Arrhenius law:
ln k = -Ea/R × 1/T + ln(A)
You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).
Using the values you will obtain:
y = -2006,9 x +23,147
As R = 8,314472x10⁻³ kJ/molK:
-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹
<em>Ea = 16,7 kJ/mol</em>
Pre-exponential factor is:
ln A = 23,147
A = e^23,147
<em>A = 1,13x10¹⁰</em>
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I hope it helps!
Answer:
2.038 seconds.
Explanation:
So, in the question above we are given the following parameters in order to solve this question. We are given a rate constant of 0.500 s^-, initial concentration= 0.860 M and final concentration= 0.310 M,the time,t =??.
Assuming that the equation for the first order of reaction is given below,that is;
A ---------------------------------> products.
Recall the formula below;
B= B° e^-kt.
Therefore, e^-kt = B/B°.
-kt = ln B/B°.
kt= ln B°/B.
Where B° and B are the amount of the initial concentration and the amount of the concentration remaining, k is the rate constant and t = time taken for the concentration to decrease.
So, we have; time taken,t = ln( 0.860/.310)/0.500.
==> ln 2.77/0.500.
==> time taken,t =2.038 seconds.
The appropriate answer is d. the high specific heat capacity of water. This unique quality of water makes it suitable as an organic solvent. Specific heat capacity is the energy required to change one gram of a substance by one degree. Organic processes need to be carried out at a specific temperature. The high specific heat capacity of water ensures that environmental changes in temperature.
Answer:
200 W
Explanation:
Formula of Power is
P= W/T
where
W= Work and T= Time
so
4000/20 = 200J/s or 200 W
Answer:
True
Explanation:
The accuracy level is usually determined by the difference between the experimental and correct value. It is important to note that the smaller the difference between the average experimental value and the correct (true) value, the more accurate it is.
When the difference is large then it means the accuracy level is low and not up to the required standard.