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noname [10]
2 years ago
8

When testing water for chemical impurities, results are often reported as BDL, that is, below detection limit. The following are

the measurements of the amount of blood in a series of water samples taken from inner - city households (in parts per million):
5, 7, 12, bdl, 10, 8, bdl, 20, 6
Chemistry
1 answer:
Mumz [18]2 years ago
4 0

Answer:

The median level in the water is 7ppm

Explanation:

LoB is assessed by calculating duplicates of a blank sample and evaluating the mean result and the standard deviation (SD). After evaluating this value LOD can be evaluated conferring to LOD=LOB+1.645(SD low concentration sample ). The quantitation limit can also be got from accuracy studies. LOD's may also be evaluated based on the standard deviation of the response (Sy) of the curve and the slope of the calibration curve (S) at levels resembling the LOD according to the formula: LOD = 3.3\frac{Sy}{S}

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3 years ago
An ice cream company decides to make a new lower calorie flavor,but testers reported that the flavor wasnt as good as the origin
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Answer:

Yes, the given instance is an example of a trade-off.

Explanation:

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3 years ago
A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti
zysi [14]
            <span> Mg(OH)2(s) + 2HCl(aq) yield MgCl2(aq) + 2H2O(l)

grams HCl required = (50.6 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 63.26 grams HCl required

Since there are only 45.0 grams HCl, then HCl is the limiting reactant.

theoretical yield MgCl2 = (45.0 grams HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 58.6 grams MgCl2 </span>
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