When testing water for chemical impurities, results are often reported as BDL, that is, below detection limit. The following are
1 answer:
Answer:
The median level in the water is 7ppm
Explanation:
LoB is assessed by calculating duplicates of a blank sample and evaluating the mean result and the standard deviation (SD). After evaluating this value LOD can be evaluated conferring to LOD=LOB+1.645(SD low concentration sample ). The quantitation limit can also be got from accuracy studies. LOD's may also be evaluated based on the standard deviation of the response (Sy) of the curve and the slope of the calibration curve (S) at levels resembling the LOD according to the formula: LOD = 3.3
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Answer:
The correct option is: (D) -2.4 kJ/mol
Explanation:
<u>Chemical reaction involved</u>: 2PG ↔ PEP
Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol
Temperature: T = 37° C = 37 + 273.15 = 310.15 K (∵ 0°C = 273.15K)
Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol) (∵ 1 kJ = 1000 J)
Reactant concentration: 2PG = 0.5 mM
Product concentration: PEP = 0.1 mM
Reaction quotient:
<u>To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:</u>
<u>Therefore, the Gibb's free energy change at 37° C (310.15 K): </u><u>ΔG = (-2.45 kJ/mol)</u>