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3 years ago

11

A. Scalene B. Acute C. Equilateral D. Isosceles E. Right F. Obtuse

1 answer:

VladimirAG [237]3 years ago

3 0

Answer:

Acute

Equilateral

Step-by-step explanation:

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LuckyWell [14K]

If $x=0$ , you have

$\displaystyle\lim_{y\to0}\frac{y^3}{y^2}=\lim_{y\to0}y=0$

But if $y=0$ , you have

$\displaystyle\lim_{x\to0}\frac{x^4}{x^4}=\lim_{x\to0}1=1$

So the limit does not exist.

3 0

3 years ago

arlik [135]

-7×+6y=-11 C because of the line

3 0

3 years ago

Find the product of 503×6

Mashutka [201]

3018

Mentally,
503 = 500 + 3
500 times 6 = 3000
3 times 6 = 18
Add them up:
3018

8 0

3 years ago

The table shows some of the values of a function of the form y=ax^2+bx+c which is the value of c, the constant, the constant for

cupoosta [38]

Answer:

$c=8$

Step-by-step explanation:

Given: $y=ax^2+bx+c$

To find: c

Solution:

At $x=4,y=48$ :

$48=16a+4b+c$ (i)

At $x=5,y=73$ :

$73=25a+5b+c$ (ii)

At $x=6,y=104$ :

$104=36a+6b+c$ (iii)

On subtracting (i) and (ii),

$25=9a+b$ (iv)

On subtracting (i) and (iii),

$56=20a+2b\\\\28=10a+b \,\,\,\,(v)$

On subtracting (iv) and (v),

$a=3$

Put a=3 in (iv)

$25=9(3)+b\\25=27+b\\25-27=b\\-2=b$

Put $a=3,b=-2$ in (iii)

$104=36(3)+6(-2)+c\\104=108-12+c\\104=96+c\\104-96=c\\8=c$

5 0

3 years ago

Which of the following has the least value A. 5:7 B. 7/8 C.11/15 D.7/10

GREYUIT [131]

Answer:

A 5:7

Ste:p-by-step explanation

because you would look at what the denominator and 7 is the least and 5.

hope this helps!

5 0

3 years ago