Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
an=6+6(n-1)
Step-by-step explanation:
Answer:
Option B) y = 50
Step-by-step explanation:
We are given the following information:
Two parallel lines are crossed by a transversal.
The attached image shows the intersection of transversal and the angles.
As clear from the image, the given pair of angles form alternate interior angles.
If two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent or equal
Thus, y = 50 degree
Answer:
Step-by-step explanation:
The equation of the line in point-slope form;
y+39 = (-5/2)(x-14)
Rearrange to solve for y:
y+39 = (-5/2)x + 35
y = (-5/2)x + 4