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3 years ago

What’s the slope and equation

Mathematics

2 answers:

Pie3 years ago

5 0

Y=-10x-100

Rise over run

Alex_Xolod [135]3 years ago

3 0

Answer:

slope = -5 equation= y=-5x+100

Step-by-step explanation:

pick the x and y intercepts as your points to find the gradient that is

(20,0) and (0,100)

slope =∆y/∆x

=100/-20

= -5

take point(20,0) and (x,y) to find equation using the slope

equation becomes y= -5x+100

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Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the gi

kompoz [17]

Answer:

The general solution is

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2}$

Step-by-step explanation:

Step :1:-

Given differential equation y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

$(D^4 -2D^3+D^2)y = e^x+1$

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

$m^4 -2m^3+m^2 = 0$

$m^2(m^2 -2m+1) = 0$

$(m^2 -2m+1) this is the expansion of (a-b)^2$

$m^2 =0 and (m-1)^2 =0$

The roots are m=0,0 and m =1,1

complementary function is $y_{c} = (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x$

Step 2:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x + \frac{1}{D^{2} } e^{0x}$

$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

$I_{2}$ $= \frac{1}{D^2(D-1)^2}e^{0x}$

$\frac{1}{D} \int\limits {1} \, dx= \frac{1}{D} x$

again integration $\frac{1}{D} x = \frac{x^2}{2!}$

The general solution is $y = y_{C} +y_{P}$

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2!}$

3 0

3 years ago

Saul in third in line. Enid is last in line. There are 3 children between them. What position is Enid in line?

VLD [36.1K]

Enid is seventh in line

8 0

3 years ago

Simplify 27+2(6+x) 1. 35+x^2 2.39+2x 3.27+12x 4.29+8x

Effectus [21]

Answer:

39 + 2x

Step-by-step explanation:

7 0

3 years ago

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The two cones below have the same radius, height, and

lozanna [386]

Answer:

yes

Step-by-step explanation:

The cones are not concurrent because one cone is obliquewhich makes the length of these land height is different have the same radius same volumes and same height are the cones concurrent is the corresponding slant height sorry equal .concurrent counts must have concurrent corresponding slant height with all this corresponding being concurrent

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2 years ago

For two functions, m(x) and p(x), a statement is made that m(x) = p(x) at x = 7. What is definitely true about x = 7? (2 points)

Virty [35]

A)Both m(x) and p(x) cross the x-axis at 7.
B)Both m(x) and p(x) cross the y-axis at 7.
C)Both m(x) and p(x) have the same output value at x = 7.
D)Both m(x) and p(x) have a maximum or minimum value at x = 7.

m(x) = p(x) at x = 7

True statement about x = 7.
C)Both m(x) and p(x) have the same output value at x = 7.

7 0

3 years ago

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