Question

Find (fog)(x) when f(x)=x^2-7x+12 and g(x)=3/x^2-16

Answer 1

Answer:

$f( \frac{3}{ {x}^{2} - 16 } ) = ({\frac{3}{ {x}^{2} - 16 }})^{2} - 7(\frac{3}{ {x}^{2} - 16 }) + 12 \\ = \frac{9}{ {x}^{4} - 32 {x}^{2} + 256 } - \frac{21}{ {x}^{2} - 16} + 12$