The answer:
the main formula of the circle's equation is
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius
if a point A(x', y') passes through the circle, so the equation of the circle can be written as
(x'-a)²+ (y'-b)² = R², and that is a main formula.
<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²
and we know that R= OA = OC= OB,
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies
x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)² so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
-5= -2x -4y, when x = -3 /2 we obtain y = 2
the center is C(-3/2, 2)
Answer: for plato users
D. 341 and 375
Step-by-step explanation:
I just took the test
Answer: y=
+2
Step-by-step explanation:
<em>This is y intercept form</em>
First you find the slope
Then you find the y intercept and plug it in t the equation y=mx+b
The answer is (4/5). If you multiply the first (5/12) over and over, you get this sequence.
14t^3*6t
= (14*6)*(t^3*t)
= (2*7*2*3)*(t*t*t*t)
= 2*2*3*7*t*t*t*t
