Answer : The mass of benzyl salicylate needed to manufacture 350 tubes of sunscreen are, 1.55 kg
Explanation :
As we are given that a sunscreen preparation contains 2.60 % by mass benzyl salicylate. That means, 2.60 grams of benzyl salicylate present in 100 g of solution.
First we have to convert the given mass from oz into kg.
Conversion used:
1 kg = 35.274 oz
or,
So,
Now we have to determine the mass of benzyl salicylate.
As, 100 g of solution contains mass of benzyl salicylate = 2.60 g
So, 0.1701 kg of solution contains mass of benzyl salicylate = 
Now we have to determine the mass of benzyl salicylate are needed to manufacture 350 tubes of sunscreen.
Mass of benzyl salicylate in 350 tubes of sunscreen = 0.00442 kg × 350
Mass of benzyl salicylate in 350 tubes of sunscreen = 1.55 kg
Thus, the mass of benzyl salicylate needed to manufacture 350 tubes of sunscreen are, 1.55 kg
Its a echo being used in that picture so if i was ypu you should classify my answer
Answer:
Number 1 is false
Explanation:
1.- Charged molecules are insoluble in water. The statement is false, charged molecules are soluble in water and this is the main characteristic of charged molecules.
2.- Hydrophobic molecules tend to be nonpolar and hydrophilic molecules tend to be polar. This is true, hydrophobic molecules are non polar and hydrophilic molecules are polar.
3.- Gasoline has partial positive and negative charges which allows it to dissolve in water. This is true, gasoline is soluble in water.
4.- NH3 dissolves in water because its molecules form hydrogen bonds with water. This is true, NH3 interact with water because they can form hydrogen bonds.
5.- Hydrophobic molecules prefer to interact with each other in an aqueous solution. Absolutely true, hydrophobic molecules interact among them and they isolate from the environment.
Explanation:
It is known that charge on xenon nucleus is 
equal to +54e. And, charge on the proton is 
equal to +e. So, radius of the nucleus is as follows.
r = 
= 3.0 fm
Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.
d = r + 2.5
= (3.0 + 2.5) fm
= 5.5 fm
= 
(as 1 fm = 
)
Therefore, electrostatic repulsive force on proton is calculated as follows.
F = 
Putting the given values into the above formula as follows.
F =
= 
= 
= 411.2 N
or, = 
N
Thus, we ca conclude that N is the electric force on a proton 2.5 fm from the surface of the nucleus.
