Answer : The equilibrium concentration of 
will be, (C) 
Explanation : Given,
Equilibrium constant = 14.5
Concentration of 
at equilibrium = 0.15 M
Concentration of 
at equilibrium = 0.36 M
The balanced equilibrium reaction is,
The expression of equilibrium constant for the reaction will be:
![K_c=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
Now put all the values in this expression, we get:
![14.5=\frac{[CH_3OH]}{(0.15)\times (0.36)^2}](https://tex.z-dn.net/?f=14.5%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%280.15%29%5Ctimes%20%280.36%29%5E2%7D)
![[CH_3OH]=2.82\times 10^{-1}M](https://tex.z-dn.net/?f=%5BCH_3OH%5D%3D2.82%5Ctimes%2010%5E%7B-1%7DM)
Therefore, the equilibrium concentration of will be, (C)
Answer: Stressors
Explanation:
it can deplete aquifers include changes in precipitation and snowmelt patterns
Answer:
Dissociation factor = 1.8
Explanation:
Data provided in the question:
Molecular weight of the Procaine hydrochloride = 273
Number of ions contained, n = 2
Fraction Dissociating, α = 80% = 0.8
Now,
the dissociation factor 'i' is given as:
i = 1 + α × ( n - 1 )
on substituting the respective values, we get
i = 1 + 0.8 × ( 2 - 1 )
or
i = 1 + ( 0.8 × 1 )
or
i = 1.8
