If I'm not mistaken, the answer should be B. Oxidation
Answer:
2HCI + Na2S - > H2S + 2NaCl
Explanation:
2HCI + Na2S -> H2S + 2NaCl
before reaction: 2H, 2Cl, 2Na, 1S
after reaction: 2H, 2Cl, 2Na, 1S
Answer:
Answer: 3.01 * 10^35
Explanation:
500,000,000,000 * 6.02 * 10^23
You would also need to know the mol of sodium. After knowing the mol, write down the reaction;
Na + H20 -> NaOH + H2
Use the mol ratio, to find the amount of mol of sodium hydroxide. (Remember to balance the equation first)
After you have the necessary variables, use the following formula:
mass of sodium hydroxide = mol of sodium hydroxide x molar mass (relative/formula mass of sodium hydroxide)
That is how you will find the mass of sodium hydroxide.
