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Tomtit [17]
3 years ago
13

Find the solution to the system

Mathematics
1 answer:
Mila [183]3 years ago
7 0

Answer:

The two lines meet at (-1,1)

You might be interested in
If log10x=−3 , what is the value of x ?
IgorC [24]

log10x=−3

10 ^(log10x) = 10^(-3)

10x = 10^-3

x =10 ^ -3 / 10

x = 10^-4

x = .0001

x=1/ 10000

6 0
3 years ago
How many times does 20 go into 110
Sindrei [870]

Answer:

20 goes into 110 five-and-a-half times

Step-by-step explanation:

Let's show our work:

20  +  20  +  20   +  20  +    20   +  10      

  \____\_____\____/_____/_____/

                           100

100

= 20 + 20 + 20 + 20 + 20 + 10

Half of 20 = 10

The keyword is half - so that leaves a 0.5 in your answer to "How many times does 20 go into 110."

How many 20's are there? Let's count!

20 + 20 + 20 + 20 + 20

 1      2       3      4       5

So five 20's + one 0.5 = ?

That equals 5.5, because 5 + 0.5 = 5.5

Your answer is 5.5!

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
6 0
3 years ago
) A car leaves a town at 30 miles per hour. How long will it take a second car traveling at 38 miles per hour to catch the first
Mumz [18]

Answer:

4hrs

Step-by-step explanation:

4 0
2 years ago
Help me pass . I’m depressed and school juss shot me in my back
juin [17]

Answer:

5√3 X squared

Step-by-step explanation:

Individually work them out then put in back on the fraction and once you simplify it gives you the answer.

4 0
3 years ago
Read 2 more answers
Plz help me with this
AnnZ [28]

Answer:  \bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, B=\dfrac{6}{5}  →   P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}

Half of that period is: \dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}

Calculate the period for each of the options to find a match:

A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}

7 0
3 years ago
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