We can get two different equations from this:
3x = 18
and
3x = -18
So:
x = 6, x = -6
x = {6, -6}
Answer:
Probabilty of not poor= 0.75
Step-by-step explanation:
total of 11332 bonds.
7311 are good risk.
1182 are medium risk.
Poor risk
= total risk-(good risk+ medium risk)
= 11332-(7311+1182)
= 11332-8493
= 2839.
Poor risk = 2839
Probabilty that the ball choosen at random is not poor= 1 - probability that the ball is poor
Probability of poor = 2839/11332
Probabilty of poor= 0.2505
Probabilty that the ball choosen at random is not poor= 1- 0.2505
= 0.7495
To two decimal place= 0.75
Answer: all i can say is this for an edu guess
2 6 and 4 would be 40 or 30
3 5 and 7 would be 110 or 120
8 would be 20 or 10
also this was the first answer
Answer:
![x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]](https://tex.z-dn.net/?f=x%3D%28243%29log_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D)
Step-by-step explanation:
you have the following formula:

To solve this equation you use the following properties:

Thne, by using this propwerty in the equation (1) you obtain for x
![log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]](https://tex.z-dn.net/?f=log_%7B%28%5Cfrac%7B1%7D%7B81%7D%29%7D%28%5Cfrac%7B1%7D%7B81%7D%29%5E%7B%5Cfrac%7Bx%7D%7B243%7D%7D%3Dlog_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D%5C%5C%5C%5C%5Cfrac%7Bx%7D%7B243%7D%3Dlog_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D%5C%5C%5C%5Cx%3D%28243%29log_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D)
Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
Our expression is:
.
Let's focus on the cube root of 81 first. What's the prime factorisation of 81? It's simply: 3 * 3 * 3 * 3, or
. Put this in for 81:
![\sqrt[3]{81} =\sqrt[3]{3^3*3}=\sqrt[3]{3^3} *\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B81%7D%20%3D%5Csqrt%5B3%5D%7B3%5E3%2A3%7D%3D%5Csqrt%5B3%5D%7B3%5E3%7D%20%2A%5Csqrt%5B3%5D%7B3%7D)
We know that the cube root of 3 cubed will cancel out to become 3, but the cube root of 3 cannot be further simplified, so we keep that. Our outcome is then:
![\sqrt[3]{3^3} *\sqrt[3]{3}=3\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%5E3%7D%20%2A%5Csqrt%5B3%5D%7B3%7D%3D3%5Csqrt%5B3%5D%7B3%7D)
Now, let's multiply this by 1/3, as shown in the original problem:
![\frac{1}{3}* 3\sqrt[3]{3}=\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%2A%203%5Csqrt%5B3%5D%7B3%7D%3D%5Csqrt%5B3%5D%7B3%7D)
Thus, the answer is
.
<em>~ an aesthetics lover</em>