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2 years ago

The sum of the digits of a three digit number is 19. The second digit is one more than the first digit. The third

Mathematics

1 answer:

Oxana [17]2 years ago

5 0

Answer:

D. 568

Step-by-step explanation:

Let the number is in the form of xyz

Sum of the digits is 19

x + y + z = 19

The second digit is one more than the first digit

y = x + 1

The third digit is two more than the second digit

z = y + 2 = x + 1 + 2 = x + 3

<u>Substitute the values of y and z</u> into the first equation and solve for x

x + x + 1 + x + 3 = 19
3x + 4 = 19
3x = 15
x = 5

<u>Find the value of y and z</u>

y = 5 + 1 = 6
z = 5 + 3 = 8

The number is 568

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$\qquad\qquad\huge\underline{{\sf Answer}} \huge♨$

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