Question

The sum of the digits of a three digit number is 19. The second digit is one more than the first digit. The third

Answer 1

Answer:

• D. 568

Step-by-step explanation:

Let the number is in the form of xyz

We have

Sum of the digits is 19

• x + y + z = 19

The second digit is one more than the first digit

• y = x + 1

The third digit is two more than the second digit

• z = y + 2 = x + 1 + 2 = x + 3

Substitute the values of y and z into the first equation and solve for x

• x + x + 1 + x + 3 = 19
• 3x + 4 = 19
• 3x = 15
• x = 5

Find the value of y and z

• y = 5 + 1 = 6
• z = 5 + 3 = 8

The number is 568