<span>A trait that improves the fitness of its bearer, compared with individuals without the trait.</span>
Answer:
Explanation:
<em>Let the ability to break down the red color in beets be represented by the allele </em><em>B</em><em>. The inability would be represented by the allele </em><em>b</em><em>.</em>
A nonsecretor's genotype would be BB or Bb while a secretor's genotype would be bb.
A nonsecretor woman with a secretor father would be a carrier with genotype Bb. A nonsecretor man who in a previous marriage had a secretor daughter would also be a carrier with genotype Bb. If the two marries:
<em>Bb x Bb</em>
<em> BB 2Bb bb</em>
1.
(a) probability of their first child will be a secretor girl = probability of having a girl and being a secretor.
Probability of having a girl = 1/2
Probability of being a secretor = 1/4
<em>probability of their first child will be a secretor girl</em> = 1/2 x 1/4 = 1/8
(b) Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor.
Probability of having a girl = 1/2
Probability of being a nonsecretor = 3/4
<em>Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor</em> = 1/2 x 3/4 = 3/8
2. <em>Probability that their first two children will be nonsecretors of either sex = probability of their first being a nonsecretor and of either sex and probability of their second being a nonsecretor and of either sex.</em>
= 3/4 x 3/4 = 9/16
The answer is true they should have both
