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KonstantinChe [14]
3 years ago
6

Helpppppppppppppppppppp

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0

Answer:

olm

Step-by-step explanation:

dont know which sub is this?

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Which of the following events are independent?
Svetach [21]

Answer:

1 only

Step-by-step explanation:

because it talks about a coin and a dice and the rest is about cards

6 0
3 years ago
What is the answer to 10k-9=9k + 10?
oee [108]
K=19 which would leave the equation 181=181. The first step to solving this is subtracting 9k from each side.
after you do that it should be k-9=10
now you add 9 to both sides leave k=19. plug k into the equation and get 181=181
7 0
3 years ago
Find the period of the graph shown below<br> A. 4π<br> B. π<br> C. 2π<br> D. 2/3π
4vir4ik [10]
A I believe is the answer
8 0
3 years ago
Read 2 more answers
Diagram 5 shows a triangle ABD such that AD = 17 cm, AB = 10 cm and BD = 21 cm. The straight line AC is perpendicular to the str
OlgaM077 [116]

Answer:

8

Step-by-step explanation:

100 = x^2 + AC^2

17^2 = AC^2 + (21 - x)^2

289 = AC^2 + 21^2 + x^2 - 2*21*x

289 =<u> AC^2</u> + 441 +<u> x^2</u> - 42x

from 1st equation AC^2 + x^2 = 100

289 = 441 + 100 - 42x

289 = 541 - 42x

42x = 541 - 289 = 252

x = 252/42 = 6

so AC^2 = 100 - 6^2 = 100 - 36 = 64

AC = 8

7 0
2 years ago
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
1 year ago
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