A.
the starting point is where t=0
d(0)=-16(0)^2+96(0)+112
D(0)=112
started from 112 feet
b. max height is vertex
for
y=ax^2+bx+c
the x value of the vertex is -b/2a
so
D(t)=-16t^2+96t+112
t value of vertex is -96/(2*-16)=3
it reaches after 3 seconds
C. simpliy evaluate D(t) for t=3
D(3)=-16(3)^2+96(3)+112
D(3)=-16(9)+288+112
D(3)=-144+400
D(3)=256
max height is 256ft
Answer:
Depth of the submarine = 668.09 feet
Step-by-step explanation:
From the figure attached,
In triangle ABC,
Distance between a navy cruiser and a nuclear submarine = 2500 feet
Angle between the water level and the submarine = 15.5°
By applying sine rule in the given triangle,
sin(∠BAC)° = 
sin(15.5°) = 
BC = 2500[sin(15.5)]
BC = 668.09 feet
Therefore, submarine is 668.09 feet deep in the sea.
Answer: 10.5 gallons, or 11 if you need to use a whole number
You must follow the correct order of operations. Start working inside the parentheses and do the multiplication first.
2 × (5 + 3 × 2 + 4) =
= 2 × (5 + 6 + 4)
Now do the additions inside the parentheses.
= 2 × (11 + 4)
= 2 × 15
Now you do the multiplication.
= 30
Answer: 30
